A volume of 80.0 mL of a 0.790 M HNO Calculate the volume of KOH required...

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Question

Answer 1

Answer #1

At equivalence point, moles of acid males of base I MROH VROH = MANO VINO MROH = 0.650M MANO, < 80ml Vkен - 2 VHNO, = 0.790 M

Answer 2

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