Draw an MO diagram for trans-RuBr2Cl4. The molecule has point group symmetry of D4h with a...

Question

Question

Draw an MO diagram for trans-RuBr2Cl4. The molecule has point group symmetry of D4h with a character table attached below. Please show all steps.

Dan |E 20, Cz 2C, 20일 i | 1 25sq 1 20, 1 1 1 1 1 1 -1 1 1 | 1 204 | 11 + 22 -1 I R . xy xy 0 | (R, R.) | -11 1 |2 1 -1 0 1 (x

Γ 6 2 2 2 0 0 0 4 4 2

Answer 1

Answer #1

RuBr₂Cl₄ is a 14 electron complex.

central metal Ru has 8 valence electron and each halide ligands give 1 electron each.

MO diagram for D4h symmetry wold be:

a2u alg big b2g eg a2g, a2u.b2g,b2u,eg, eu alg alg,big, eu alg+big+b2g+eg b2u eu— ...... .......... eut bigth alg 46

Answer 2

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