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Question 12 1 pts Using the thermodynamic data below, calculate for the conversion of oxygen to ozone, 30,() 203) at 2000.0 K
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Answer #1

Given:

Hof(O2(g)) = 0.0 KJ/mol

Hof(O3(g)) = 142.3 KJ/mol

Balanced chemical equation is:

3 O2(g) ---> 2 O3(g)

ΔHo rxn = 2*Hof(O3(g)) - 3*Hof( O2(g))

ΔHo rxn = 2*(142.3) - 3*(0.0)

ΔHo rxn = 284.6 KJ

Given:

Sof(O2(g)) = 205.0 J/mol.K

Sof(O3(g)) = 237.6 J/mol.K

Balanced chemical equation is:

3 O2(g) ---> 2 O3(g)

ΔSo rxn = 2*Sof(O3(g)) - 3*Sof( O2(g))

ΔSo rxn = 2*(237.6) - 3*(205.0)

ΔSo rxn = -139.8 J/K

ΔHo = 284.6 KJ/mol

ΔSo = -139.8 J/mol.K

= -0.1398 KJ/mol.K

T = 2000 K

use:

ΔGo = ΔHo - T*ΔSo

ΔGo = 284.6 - 2000.0 * -0.1398

ΔGo = 564.2 KJ/mol

We have:

T = 2000 K

ΔGo = 564.2 KJ/mol

ΔGo = 564200 J/mol

use:

ΔGo = -R*T*ln Kc

564200 = - 8.314*2000.0* ln(Kc)

ln Kc = -33.9307

Kc = 1.84*10^-15

Answer: 1.84*10^-15

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