Question

Would some please explain how to solve this problem and what I did wrong? Also, sorry the handwriting is atrocious, I was doing it in a hurry.

An unknown compound contains only C. H and O. Combustion of 7.00 g of this compound produced 14.0 g CO, and 5.73 g H,O. What is the empirical formula of the unknown compound? Insert subscripts as needed. empirical rmula: C,H,O

also could you explain how this could possibly be wrong

Answer 1

U empirical formula combustion - 7.009 co2 produced = 14:0g H₂o produced = 5.739. moles of co2 = 14.0 g x 14. og Imole of co2 44.019 = 0.317 moles of co. moles of H₂O 5.739 x 1 mole of ho 18.01 = 0.318 moles of H₂O moles = moles of co of carbon by measuring 0.317 nol x 12 g imol a = 3.804g. moles of hydrogen by measuring moles of ho = 2x 0.318 × 1.00794 - 0.641 g (every moles of hydrogen and H₂0 contain I mole of 2 moles of oxygen) And balance mass was oxygen. 1 700 - 3.804 - 0-641). "2.559 Scanned with CamScanner

molar quantity, 15.99 g/mol 0.159 mol. So we we got got molar Cill and o. quantities to with respect C 0.317 0.159 H 0.318 0:159 0 0.159 0.159 (1.9902). = Ca H. o. and this represents the empirical formula. ( of the moles step of done H₂O for is calculation wrrong). Net iconic equation Huo (aq) + NaOH (aq) - Nacho, laq) the oce) I HO cannot because it Croma alund be is it separated into cons not an aqueous is a lig ud.

I Hence Hoo is a weak acid (Not dissociate) complete conic Hlo aq) + Na aut on iag Equation - is Ho (1) + Na tle O₂ (aq). Nat and doi are spectation cons ions. . a on cancelling spectata i we get Net lonic Equation of HClO₂ (aq) + OH (aq) - H₂0 (1) + clon (aq) las Scanned with CamScanner