standard deviation is 15. Compute the p-value and state your conclusion for each of the flowing...
| A sample of 100 is used and the population standard deviation is 15 Compute the p-value and state your conclusion for each of the following sa ple esults use -0.01. Round z value to two decimal places and p-value to four decimal places. If your answer is zero, enter "O". Enter negative value as negative number. MacBook Air
Ha:μ<85 A sample of 140 is used and the population standard deviation is 10, Compute the p-value and state your conclusion for each of the following sample results. Use a-0.01 Round z value to two decimal places and p-value to four decimal places. If your answer is zero, enter "O". Enter negative value as negative number a. 82.5 z value p-value conclusion reject b.82 Ho z value p-value conclusion reject Ho C.80 z value p-value conclusion reject d. 86.5 Ho...
A sample of 120 is used and the popdation standard deviatien is 15 Compute the Pwhn·nd state wur co ch slon for each of the fol value to four dedimal places. If your answer is zero, enter ". Enter negative value as negative number ing sample results. Use o-0.0 R ur d·wal e tu two decind places a z value p value conclusion Select your answer b-75.5 H e value p value 74 a value P-value conclusion -value p-value conclusion...
Consider the following hypothesis test: Но:#287 Ha:p< 87 A sample of 110 is used and the population standard deviation is 15. Compute the p-value and state your conclusion for each of the following sample results. Use a0.05. Round z value to two decimal places and p-value to four decimal places. If your answer is zero, enter "O". Enter negative value as negative number. a.85.5 z value p-value conclusion - b. 83 Select your answer - H z value p-value conclusion...
Consider the following hypothesis test: H0: m>=76 Ha: m<76 A sample of 140 is used and the population standard deviation is 12. Compute the p-value and state your conclusion for each of the following sample results. Use a=0.02. Round z-value to two decimal places and p-value to four decimal places. If your answer is zero, enter "0". Enter negative value as negative number. a. x=73.5 z-value ________ p-value ________ Conclusion: (Reject/Do Not Reject) H0 b. b. x=72.5 z-value ________ p-value...
H0: p ? 0.75 Ha: p < 0.75 A sample of 300 items was selected. Compute the p-value and state your conclusion for each of the following sample results. Use standard deviation = .05. Round your answers to four decimal places. a. = 0.66 p-value is Conclusion: p-value is H0 b. = 0.72 p-value is Conclusion: p-value is H0 c. = 0.7 p-value is Conclusion: p-value is H0 d. = 0.77 p-value is Conclusion: p-value is H0
Can you help with the P-VALUE, and Conclusion.^^ Test stat, Critical value and conclusion please^^ *8.2.22 Assume that the significance level is a 0.01. Use the given information to find the P-value and the critical value(s) 1 pthe test statistic is z= -1.93. With H Click here to view page 1 of the Normal table. Click here to view page 2 of the Normal table P-value 0.0268 (Round to four decimal places as needed.) A sample mean, sample size, and...
Consider the following hypothesis test. Ha: μ < 50 A sample of 36 is used. Identify the p-value and state your conclusion for each of the following sample results. Use -0.01. X (a) 49 and s-5.2 Find the value of the test statistic. (Round your answer to three decimal places.) Find the p-value. (Round your answer to four decimal places.) p-value State your conclusion. Do not reject Ho There is insufficient evidence to conclude that u 50 O Reject Ho....
Conduct the hypothesis test and provide the test statistic, critical value and P-value, and state the conclusion. A package of 100 candies are distributed with the following color percentages: 12% ed, 22% orange, 15% yellow, 10% brown, 25% blue and 16% green. Use the given sample data to test the claim that the color distribution is as claimed. Use a 0.01 significance level 囲 Click the icon to view the color counts for the candy in the package. The test...
A random sample of 49 measurements from a population with population standard deviation σ1 = 3 had a sample mean of x1 = 8. An independent random sample of 64 measurements from a second population with population standard deviation σ2 = 4 had a sample mean of x2 = 10. Test the claim that the population means are different. Use level of significance 0.01. 1. Compute x1 − x2 and x1 − x2 = 2. Compute the corresponding sample distribution...