Question

*8.2.22 Assume that the significance level is a 0.01. Use the given information to find the P-value and the critical value(s) 1 pthe test statistic is z= -1.93. With H Click here to view page 1 of the Normal table. Click here to view page 2 of the Normal table P-value 0.0268 (Round to four decimal places as needed.)

Can you help with the P-VALUE, and Conclusion.^^

Test stat, Critical value and conclusion please^^

Answer 1

1)
Here, z = -1.93

p value = 0.0536

As p value> 0.01 fail to reject the null hypothesis

2)

Below are the null and alternative Hypothesis,
Null Hypothesis: μ = 40
Alternative Hypothesis: μ ≠ 40

Test statistic,
z = (xbar - mu)/(sigma/sqrt(n))
z = (41 - 40)/(8/sqrt(25))
z = 0.63

Rejection Region
This is two tailed test, for α = 0.05
Critical value of z are -1.96 and 1.96.
Hence reject H0 if z < -1.96 or z > 1.96

As the value of test statistic, z is outside critical value range, fail to reject the null hypothesis