1)
Direction, theta = arctan (52.2/-26.2) = - 63.35 degree
Direction, theta = 360 - 63.35 = 296.65 degree
2)
net horizontal distance
Dx = - 3.1 km
net vertical distance
Dy = 3.3 - 5.1 = - 1.8 km
a)
net displacement, D ^2 = Dx^2 + Dy^2
D^2 = 3.1^2 + 1.8^2
D = 3.585 km
b)
Direction
x = arctan ( 1.8/3.1)
x = 30.14 ccw from west.
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do comment in case any doubt will reply for sure.. Goodluck
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