1.
Time for entire play = Time of travel for the ball from Bill to carlos + Time of travel for carlos
t = t1 + t2
d1 = distance traveled by the ball between Bill and Carlos = 45 m
v1 = velocity of the ball between Bill and Carlos =15 m/s
Time of travel for the ball from Bill to carlos is given as
t1 = d1 /v1
t1 = 45/15 = 3 sec
d2 = distance traveled by the Carlos = 60 m
v2 = velocity of Carlos =7.5 m/s
Time of travel for carlos is given as
t2 = d2 /v2
t2 = 60/7.5 = 8 sec
hence total time of travel is given as
t = t1 + t2 = 3 + 8 = 11 sec
2)
Total distance traveled by ball = distance traveled by ball from Bill to carlos + distance traveled by carlos carrying the ball =
D = d1 + d2 = 45 + 60 = 105 m
3)
Total displacement is given as
D' = d1 - d2
D' = 45 - 60
D' = - 15 m
hence the magnitude of displacement is smaller than the magnitude of the distance traveled
Lab 3: Your turn to practice Turn this in - it is a graded lab activity...
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