Here we use TI-83 calculator .
Follow the path :
STAT > TESTS > 4 : 2 - SampTTEST
Select Input : Stats and enter the values , select hypothesis. Pooled : No.
So we get the output as :
a) The test statistic is given by
t = 2.212
b) The degrees of freedom are
df = 68.94 69
c) P value = 0.0303
d)
Here p value < ( 0.05 )
Reject H0. There is sufficient evidence to conclude that
.
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