Given that, sample size ( n ) = 50
sample mean = 14.09
population standard deviation = 3
The null and alternative hypotheses are,
a) Test statistic is,
b) p-value = 2 * P(Z < -2.14) = 2 * 0.0162 = 0.0324
=> p-value = 0.0324
c) Since, p-value = 0.0324 <
=> Reject H0. There is sufficient evidence to conclude that
d) critical values at are, z* = ± 1.96
Rejection rule is,
test statistic -1.96
test statistic 1.96
Since, test statistic = -2.14 < -1.96
=> Reject H0. There is sufficient evidence to conclude that
-6 points You may need to use the appropriate appendix table or technology to answer this...
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