Question
a.) what is the claim? identify H0 and Ha
b.) find the critical values and rejection region
c.) find the standarized test statistic z
An energy company wants to choose between two regions in a state to install new producing wind turbines Aresearcher claims th
(b) Find the critical value(s) and identify the rejection region. The critical value(s) is/are zo = (Round to three decimal p
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From given data,

An energy company wants to choose between two regions in a state to install energy-producing wind turbines. A researcher claims that the wind speed in Region A is less than the wind speed in Region B. To test the regions. the average wind speed is calculated for 60 days in each region. The mean wind speed in Region A is 13.8 miles per hour. Assume the population standard deviation is 2.7 miles per hour. The mean wind speed in Region B is 15.2 miles per hour. Assume the population standard deviation is 3.2 miles per hour. At \alpha = 0.05. can the company support the researcher's claim?

a.) what is the claim? identify H0 and Ha

What is the claim :

Claim : The wind speed in Region-A is less than the wind speed in Region-B

identify H0 and Ha

Null hypothesis : H0 : \mu _{A} > \mu _{B}

Alternative hypothesis : Ha : \mu _{A} < \mu _{B} (Left tailed test)

b) Find critical value and identify the rejection region

level of significance \alpha = 0.05

From the standard normal tables ,it is observed that the z-critical value at the 0.05 level of significance is -1.645.

Decision rule : Reject H0 when Zstatistic < -1.645.

(c) Find the standardized test statistic z.

Calculate the test statistic value,

Z = ( \bar{x}_{A} - \bar{x}_{B} ) / sqrt(\sigma _{A}^{2} / n _{A} + \sigma _{B}^{2} / n _{B} )

Z = ( 13.8 - 15.2) / sqrt((2.7)2 / 60 + (3.2)2 / 60 )

Z = -1.4 / 0.540524437

Z = - 2.590077

Z = - 2.59 (Rounded to two decimal places)

Hence , the required test statistics is - 2.59

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