Question

PRACTICE IT Use the worked example above to help you solve this problem. A uniform ladder I 10.0 m long and weighing W52.9 N rests against a smooth vertical wall. If the ladder is just on the verge of slipping when it makes a 0 47.00 angle with the ground, find the coefficient of static friction between the ladder and ground. 0.536 X Your response differs from the correct answer by more than 10 %. Double check your calculations. EXERCISE HINTS: GETTING STARTED I I'M STUCK! If the coefficient of static friction is 0.383, and the same ladder makes a 64.0° angle with respect to the horizontal, how far along the length of the ladder can a 71.8-kg painter climb before the ladder begins to slip? m Need Help? Read It Talk to a Tutor

Answer 1

Soli Given: length of ladder, t= 10.0m Weight, W= 52.9N 0 = 47.00 Bk N f.B.D tie UN fiz Nz hii (Efn:o). N =W= 52.9 N Taking moment about P ( Clockwise the WeW90 - Nel sino = 0 W -529 N₂= 2tano 2 tan(47) N2= 24.665N fi= N2 ung = N₂ = 11x52.9 = 24.665 a=0.466 . - friction. U=0.466 Coefficient of e Nz Exercise M = 0.383. W = 52.9N. Wm= 71.8*9.8=703.64 N 0=640 N, = Wet Wm= 52.9+703.64 756.54N UN = 0.3838.7 56.54 289.SN $,- N2= 289.750 Taking moment abat p

let PB an clockwise moment = the Wexl caso & Wm & caso - Nad sino =0 Win a caso = Nel Sino-wlcoso. 756.54 x2x6964)= 289.75% 10% Sin(64) + 52.9% 10xc0364 2 ♡ 331064a= 2604025 +115.94 la = 8.2m | Aling the length of ladder,