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If a 5-kg bowling ball is projected upward with a velocity of 2.0 m/s, then what...

If a 5-kg bowling ball is projected upward with a velocity of 2.0 m/s, then what is the recoil velocity of the Earth (mass= 6x10^24 kg).

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Answer #1

Solution)

We know here,

Bowling momentum= mass * velocity

0= mass bowling* velocity initial + mass of earth* velocity of earth

So, velocity of earth= - (m bowling/ m earth). Vinitial

V= -5kg/(6*10^24 kg)*2 m/s

V= -1.7*10^-24 m/s

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