Question

please please i need help with a,b,,c

A 14.0 m uniform ladder weighing 490 N rests against a frictionless wall. The ladder makes a 63.0-angle with the horizontal (a) Find the horizontal and vertical forces (in N) the ground exerts on the base of the ladder when an 830-N firefighter has climbed 3.80 m along the ladder from the botto horizontal force magnitude direction 239.62 towards the wall vertical force magnitude 239.62 What forces act in the vertical direction? N direction (b) If the ladder is just on the verge of slipping when the firefighter is 9.40 m from the bottom, what is the coefficient of static friction between ladder and ground? 0.323 It may be helpful to think first about the force the wall exerts on the ladder. How is this related to the force that the ground exerts on the ladder? (c) What IT? If oil is spilled on the ground, causing the coefficient of static friction to drop to half the value found in part (b), what is the maximum distance (in m) the firefighter can climb along the ladder from the bottom before the ladder slips? m

Answer 1

F. Bol of ladder RB 490N) gray. RANGA. 630 ca) Ladder is in equilibrihem. i net torgia and Net Fore are o B Let's take torque at point A TA= 8:306o$63°x3.85+490 0163x75 ARB Sim63 x 1420 Take gative, Csine Rp. Si'm63x14 =( 30x 3.8+4920x7)(0563º. | RB = 239.62N In horizontal direction? Horizontal Force Rans 29962 wf from ground - Darston is towards wall. In vertaal direction't Rag 1-820-490=0 | Ray=1320N/ Direction is upwards. Vertical Force from ground- (b) Ladder slops when firefighter is it acuma RB-Ran 20. TA=8 30 CA6949. 45+4906847275+Rp.Sim63X1420. Rosime38145830x9_4749047)24630 , TRB=408.7850] This is fraction forre Ran 2408.788 Not provided by ground 408.78524 x 1320, M=0.309 co alberat de stade fato

(c) Now u is tuduced to half;'. Now 120.15. .. Ran20:15X13201 Ran=1980.,. RB=1980. TA 28306046 38 X+4906463977+ha Simb 3 81420 · 198x3163*814 = (8301749037) 6363°. me Forefighter con climb 2-42 m H= 2.42 m along ladder from bottom of grainal