Question
consider the solubility of a mineral. It is a FeS(s) mineral. S is -2 oxidation state. The mineral is found in a mud solution, see the following chemical equation which is under equilibrium in the atmosphere. Btw S is -2 oxidation State.
FeS(s) + 2H+ = Fe2+ + H2S(g)
1) If the condition is at 25 degrees C, pH=4.2, Fe2+ concentration is 4 ppm, and logK= 3.0. What is the partial pressure of H2S(g) under the equilibrium?
2) Hydrogen sulfide gas has the lowest Olfactory threshold (begin to smell), which expressed as .01 microgram/L (H2S^0). The following equation is when H2S dissolved in water.
does the mineral under the mud solution stink?


H2S(g) = H2S°(aq) log K=-1.00
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Answer #1

This question is solved as follows:

Sol-it We Fes(s) + 2H+ = Fe2+ + H₂S(g. are given, T = 25°C. PH = 4.2, [Feet = 4ppm = 4 mg/litre logk=3.0. We know, equilibriuPris = 0.055588 at Ang

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