Question

The figure gives an overhead view of the path taken by a 0.169 kg cue ball as it bounces from a rail of a pool table. The ball's initial speed is 1.59 m/s, and the angle @1 is 55.9º. The bounce reverses they component of the ball's velocity but does not alter the x component. What are (a) angle 82 and (b) the magnitude of the change in the ball's linear momentum? (The fact that the ball rolls is irrelevant to the problem.) (a) Number Units (degrees) - (b) Number 0151 UnitsT kg.m/s or N.S

Answer 1

7 - - u xolo T Herce m = 0.16ang Initial velocity (ū) 159m's de 55.900 uz ucoscej tusu e usino, it neaso, j e We using î - v cosa i (W Harce usino = wsino, and ucoso, - - v cosez 9. u=v and sincera sine, (a) o 2 55.90 How change in momentum AP²2 mei-uda - Qumosol so AP= 2x 1.598 0.169 x cos ss.go PPP = 0.3013 kgm/s or ns/ Please put you're thumb dear