Molar mass of CH3OH,
MM = 1*MM(C) + 4*MM(H) + 1*MM(O)
= 1*12.01 + 4*1.008 + 1*16.0
= 32.042 g/mol
use:
mass of CH3OH,
m = number of mol * molar mass
= 0.42 mol * 32.04 g/mol
= 13.46 g
Answer: 13 g
Methanol (CH3OH) is used in the production of many chemicals. methanol is made by reacting carbon monoxide and hydrogen at high temperature and pressure. CO(g) + 2H2(g) ==> CH3OH(g) a) How many moles of each reactant are needed to produce 3.60 x 10^2 g CH3OH? b)Calculate the number of grams of each reactant needed to produce 4.00 mol CH3OH. c)How many grams of hydrogen are necessary to react with 2.85 mol CO?
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