how man grams of KClO3 are in a 0.01856 mol sample and how many are in...
If the percent yield for the following reaction is 65.0%, how many grams of KClO3 are needed to produce 42.0 g of O2? 2 KClO3(s) → 2 KCl(s) + 3 O2(g)
C12H22O11 + 8 KClO3 12 CO2 + 11H2O + 8 KCl How many grams of reactant remain in excess after 3 grams of C12H22O11 and 18 grams of KClO3 react? Show all steps and work.
C12H22O11(s) + 8 KClO3(s) -> 12 CO2(g) + 11 H2O(g) + 8 KCl(s) KClO3 = 122.6 g/mol sucrose = 342.3 g/mol CO2 = 44.01 g/mol 1 skittle = 0.84 grams of sucrose How many grams of reactant remain (excess) after 2.5 g sucrose and 25.0 g KClO3 react?
If 3.50 kJ was required for the following reaction, how many grams of KClO3 was produced? 2 KCl (s) + 3 O2 (g) → 2 KClO3 (s) ΔH = 84.9 kJ If there are 5.96 g of NO present, how much energy (kJ) will be produced? 2 NO (g) → 2 N2 (g) + O2 (g) ΔH = -180.0 kJ
C12H22O11(s) + 8 KClO3(s) -----> 12 CO2(g) + 11 H2O(g) + 8 KCl(s) KClO3= 122.6 g/mol sucrose= 342.3 g/mol CO2= 44.01 g/mol 1 skittle= .84 grams of sucrose 1. If each skittle contains 0.84 g of sucrose (C12H22O11) What is the minimum number of skittles needed to maximize the product if I use 12.0g of KClO3? 2. How many grams of reactant remain (excess) after 2.5g of sucrose and 25.0g KClO3 react? 3. If 2.2 grams of CO2 are produced,...
If the percent yield for the following reaction is 51.0%, how many grams of KClO3 are needed to produce 32.0 g of O2? 2. 2 KCIO3(s)2 KCI(s) + 3 O2(g)
The potassium chlorate (KClO3, 122.55g/mol) in an 0.1862g sample of an explosive was determined by reaction with 50.00mL of 0.01162M Fe2+ in the following reaction: ClO3- + 6Fe2+ + 6H+ --> Cl- + 3H2O + 6Fe3+. Calculate the percentage of KClO3 in the original sample.
Small quantities of oxygen can be prepared in the laboratory by heating potassium chlorate, KClO3(s) . The equation for the reaction is 2KClO3⟶2KCl+3O2 Calculate how many grams of O2(g) can be produced from heating 70.4 g KClO3(s) STRATEGY: Convert the mass of KClO3 to moles. Convert the number of moles of KClO3 to the number of moles of O2 . Convert the number of moles of O2 to grams. Step 1: 70.4 g KClO3 is equal to 0.574 mol KClO3...
For the reaction shown, calculate how many grams of oxygen form when each of the following completely reacts. 2KClO3(s)→2KCl(s)+3O2(g) 2.73g KClO3 0.336g KClO3 89.6g KClO3 20.5g KClO3
How many grams of NaOH are in 0.10 mol NaOH? A. 4.0 grams B. 40 grams C. 400 grams D. 6.64 *10^23 grams E. 6.0*10^22 grams