mole of HC9H7O4 = mass/ molar mass
= 3.6/180 = 0.02 mol
concentration = no of mole / volume
= 0.02 mol / 1 L
= 0.02 M
now,
HC9H7O4 + H2O < ==========> C9H7O4- + H3O+
I 0.02 0 0
C -x +x +x
E 0.02 - x x x
at equilibrium, [H3O+] = x = 10-pH = 10-2.6 = 0.0025 M
now, Ka = [C9H7O4-][H3O+] / [HC9H7O4]
= x2 / 0.02 -x
= 3.57 * 10-4
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