Question

Please show your work!

P Isotherms Next two problems have to do with the following situation. A sample of monatomic ideal gas is changed from state A to state D. The gas first undergoes an isobaric process A - E and then an isothermal process E - D. Note that relevant parameters (pressures and volumes) are directly given on the graph. (Note that these problems are 2 atm--4-- directly taken from your HW assigned during a class. We have also solved an almost identical problem in class. See your class notes and my lecture slides.) 1 atm 4L SL16L 17. (2 points) Find the total work done by the gas. 18. (3 points) Find overall change in internal energy of the gas.

Answer 1

for I to E Work done WAE = 9 P= 2 atm = 2.0265 x 10's par - 3 av= change in volume 8-4 4L = Uxlo WAE = 2:0265 x105x4x103 = 9.106x10² J Fon EAD Let temperature at E= T TEPV - 2x% -195.12 K WED = RT en ( 2 ) = 8.314x195.12 en (16) = 1124.45 J Total work done W = 810.6+1124.45= 1935.053 0.082 18. For A to E Temperature at A T = 2x 4 = 97.56K 40.082 Heat chorge oQ = cooT Cp = FR to Ua= x8.314x (195.12-97.56) = 220 2027.78 Jan do = Qutaw Change in internal energy AUF 2027.78 - 1935.05=92.735 J Work done for E to D is zero as it is isotherma Total Au=92.7353 A