Question

can you please help with writing up the calculations with formulas for one- way ANOVA for a null hypothesis of... the output from JASP is provided with ANOVA output and descriptive output

H_o : μ₁ = μ₂

     H_a : μ₁ ≠

Descriptives - sbp
sex		Mean		SD		N
female		46.464		11.145		56
male		47.864		11.806		44

ANOVA - sbp
Cases		Sum of Squares		df		Mean Square		F		p
Note. Type III Sum of Squares
sex		48.250		1.000		48.250		0.369		0.545
Residual		12825.110		98.000		130.868

Answer 1

let, A denotes the factor 'sex'. Now, A has two categories Al kerale, mode sizes Ni & Na respectively. Az Ramale) with Total for ith class – Tio, 12112 Hener Tio = (460w bu x 56) = 2601.984 - Şts - Niy Tro 2 (47.864x44) = 2106•016 = 54 2; = N242 grand total & Too Ti = Tio & Tro 2. 4708 Total sa TS. n = NetNz = 100

Again, omale a t Eis - G - 1 syn = (11.14s)² + (464642. 2) Ey = 56 [(1 245) ? 46.464}] 3 1 278541402 llly Vmale = {yzj - 52 -) Syysuux (1.806)? (27-stuj] a 106935.142

TSS Syn - Too = (y + 7 ) - Too = [127854.602+ 100135.142] - (47083 n- with df = 2 12 873.36 21000 -aq SS (Sea) - STU - To - (2.601.184); (2106,016)? (4 703)2 = 48.25 with df = k-1 =27 SSE :TSS-SS (Sen) = 12873.36-48.25 = 12825.11 with df 0 nok 100-2 MSA MSC Sea) = SSC Sen) = 48.250 MSE 2 SS € /98 = 130.868 i Test statistic - Pod obsd F = MSA/MSE. & U8.250/130.868 20.369 Therefore, p-vatele = P(Frobsd F) (FF, 98) 20.54570.05 Hence, we do not reject Ho that means are equalo