Ans.3
As per Black Scholes Model with dividend
we have
C= (S-D.e-xt) N(d1)- X e-rT N (d2)
Where
C= Price of the call option=?
S= Price of underlying stock= $102
X= Option Exercise price= $100
r= Risk Free rate of return=3%
σ= Standard Deviation=0.30
D= Dividend per stock= $10
t= 90 days i.e., 90/360=1/4 years
T= 180 days i.e.. 180/360= 1/2 year
N()= Area under normal curve
d1= (Log((S-D*e-rt)/X)+(r+σ2/2)T)/σ T1/2
d2= d1- σ T1/2
Substituting the above given values for finding out N(d1) and N(d2)
we get as follows
d1=( Log((102-10*e-0.03*0.25)/100)+(0.03+(0.3)^2/2)0.5)0.3*0.5^1/2
d1= (Log((102-10*.9925)/100)+0.0375)/0.212
= (log(92.075/100)+0.0375)0.212
= (-0.03586+0.0375)/0.212
=0.00164/.212
=0.007735
Now
d2= d1-σ T1/2
d2= 0.007735-0.212
d2= -0.2043
so, C= (S-D*e-xt)* N(d1)- X e-rT N(d2)
C= 92.075* N(0.007735)-100*1.0151* N(-0.2043)
C= 92.075*0.503085-101.51*.41906
C=46.32-42.53
C=3.79
Now we can use formula of put call parity to find the value of put:-
S+P=C+X*e-rT
102+P=3.79+100*1.0151
P= 105.3-102
P= $3.30
Value of put option is decreases from $6.84 to $3.30
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