Question

4. A mixture initially containing 0.075 mol L-of HCl(g) and 0.033 mol L-l of O2(g) is allowed to come to equilibrium at 480°C where the concentration of gaseous Cl2 was found to be 0.030 mol L-7. 4 HCl(g) + O2(g) <=> 2 C12(g) + 2 H2O(g) a) Give the general expression for K, for this system in terms of the concentrations C; remembering that each c; is divided by the standard concentration cº. b) What are the equilibrium concentration of the other three gases? c) Evaluate your K, of part a) using the equilibrium concentrations given in part b). [Kc = 890] d) What is the value of Ę? e) Give the general expression for K, for this system in terms of the initial concentrations Cio and F. f) Evaluate your K of part e) using the given values for the initial concentrations and the x from part d). ande

Answer 1

Giren reaction is 4 HCl (g) + Org = e cinco + 2 H2O cg) - C Tomital Conc. (Arollo) 0.075 0.033 O ° 0 0.033-0.015 = 0.018 0.030 0.030 Flond. (hool L) change.. Imoll) 0.005-40 ois 20.075 -0.060 -0-015 (4x) 2 → 69 faz) (+22) = 0.030 =>1=0.0is Equilibrium constant Kc- [Can] [cho] [cho] [ho] - [her]" [or ] Chce - conc. of Hel co, conc. of O₂ Car -conc. of cl Chio - conc-of tho [Ca] * [Co]. Equilibrium concentrations, given [cz ] = 0.030 molt! = ax (xschange of conc.) i at equilibrium (Hel] : [HCl) initial -40 - 0.075 - 2(0.030) = 0.015 mol L'. Cor] = Cozinital - x = 0.033 - 0.030/2 -0.033 -0.015 -0.018 molt [H20] - [cm] : 2x = 0.030 moll)

© from (6 ker [* (11.09 ". [her]" [o] (cla] = [ho]=o030 moli 0.018 no - initial roncentration of reactant A 0.015 molit tor] = 0.018 molit Ke= (0.030) (0.030)2 mol "Lh 0.080 x 0.050 x 0.930xo ora 0.015) mol" [4 (0.018) moll 0.065 x0.05xo ers xo Ors XOOR Kc = = 888.8 = 890/ d § - Degree of advancement of a reaction, it indicates $. nonno where where nA - equilibrium " a stoichiometre coefficent of reactant a in reaction also § = noo-nis where AB is initial conc. of products T h is is . eq. conc. of product bis stoichiometric coeffiant of 8 I . For any of reactant (let us take Hel) initial conc = 0.095 mol/L , eq: conc = 0.015 mol/l , 9:4 e = 0.095 -0.015, 0-060 = 0.015/ lassume no. of moles for unit rolume, a conta no of moles) =) { = 0.030 - 2015 - For any product (may be H2O), "B=0,030, ngono