Average acceleration = (Change in velocity) /(Time interval)
aavg = (v2-v1) / (t2 - t1)
initial velocity v1 = 0 m/s
final velocity v2 = 90 km/hr
conversion 1 km/hr = 5/18 m/s
therefore final velocity v2 = 90 km/hr = 90 *(5/18 ) = 25 m/s
time interval (t2 - t1) = 4.1 seconds
therefore aavg = (v2-v1) / (t2 - t1) = (25-0)/4.1 = 6.09756 m/s2 = 6.1 m/s
Answer is 6.1 m/s2
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