Question

Calculate 3. Complete the following data table, which is similar to the data you will have a w use proper significant figures and units for all entries and to SHOW ALL CALL ar to the data you will have after completing this lab. Be nits for all entries and to SHOW ALL CALCULATIONS! • Sample Preparation and Setup o Mass of Sample 0.198_8_- o Mass of generator (test tubes, Caco, and HCI) before reaction 75.0238_ • Determination of Volume, Temperature and Pressure of Carbon Dioxide Gas 0.0257 L Volume of CO2(g) collected 21.5°C Temperature of water 758 mm Hg - Barometric pressure Vapor Pressure of water at 21.5°C Pressure of dry CO2(g) (Equation 3) Amount of carbon dioxide gas generated 74.975 g . Mass of generator (test tubes and product) after reaction . Mass loss of generator = mass of CO2 generated o Moles of CO2 generated Volume of CO2(g) at STP (Equation 4) Molar volume of CO2(g) at STP (Equation 2)

how do we find co2?

Answer 1

Pressure of CO₂ gas = Barometric pressure - vapor pressure of Water at 21.5⁰c

= 758 - 19.2

= 738.8 mm Hg

mass of CO₂ = Mass of generator before reaction - mass of generator after reaction = 75.023 - 74.975

= 0.048 g

moles of CO₂ = (mass of CO₂ / molar mass of CO₂ ) = ( 0.048/44) = 0.001091

now using ideal gas equation

PV= nRT

volume of CO₂ at STP

V = nRT/P (1)

at STP ,

P = 1 atm

T= 273 K

R = 0.082 L-atm/mol.K

calculated moles of CO₂ (n) = 0.001091

then ,using Eq.1

volume of CO₂ at STP ( V) = (0. 001091*0.082*273/1)  = 0.0244 L

now

molar volume at STP (V_m)

= $\small \frac{V}{n}$ = ( 0.0244/0.001091) = 22.38 L