Ho : µ1 - µ2 = 0
Ha : µ1-µ2 ╪ 0
difference in sample means = x̅1-x̅2 =
22.0000 - 16.0 =
6.000
pooled std dev , Sp= √([(SS1 + SS2]/(n1+n2-2)) =
3.6742
std error , SE = Sp*√(1/n1+1/n2) =
1.5000
t-statistic = ((x̅1-x̅2)-µd)/SE = ( 6.0000
- 0 ) / 1.50
= 4.0000
Degree of freedom, DF= n1+n2-2 =
23
p-value =
0.000563 (excel function: =T.DIST.2T(t
stat,df) )
Conclusion: p-value <α , Reject null
hypothesis
answer: option B)
A researcher conducts an independent-measures study examining the effectiveness of a group exercise program at an...
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A researcher conducts an experiment on human memory and recruits 15 people to participate in her study. She performs the experiment and analyzes the results. She uses a t-test for a mean and obtains a p-value of 0.17. Which of the following is a reasonable interpretation of her results? This suggests that her experimental treatment has no effect on memory. If there is a treatment effect, the sample size was too small to detect it. She should reject the null...
A researcher conducts an experiment on human memory and recruits 15 people to participate in her study. She performs the experiment and analyzes the results. She uses a t-test for a mean and obtains a p-value of 0.17. Which of the following is a reasonable interpretation of her results? A. This suggests that her experimental treatment has no effect on memory. B. If there is a treatment effect, the sample size was too small to detect it. C. She should...
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