Question

Using standard heats of formation, calculate the standard enthalpy change for the following reaction. CaCO3(s)—*CaO(s) + CO2(

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Answer #1


Given:
Hof(CaCO3(s)) = -1206.92 KJ/mol
Hof(CaO(s)) = -635.09 KJ/mol
Hof(CO2(g)) = -393.509 KJ/mol

Balanced chemical equation is:
CaCO3(s) ---> CaO(s) + CO2(g)

ΔHo rxn = 1*Hof(CaO(s)) + 1*Hof(CO2(g)) - 1*Hof( CaCO3(s))
ΔHo rxn = 1*(-635.09) + 1*(-393.509) - 1*(-1206.92)
ΔHo rxn = 178.321 KJ

Answer: 178.3 KJ

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