Question

Some sulfuric acid is spilled on a lab bench. You can neutralize the acid by sprinkling sodium hydrogen carbonate on it and then mopping up the resultant solution. The sodium hydrogen carbonate reacts with sulfuric acid producing sodium sulfate, water, and carbon dioxide.


Sodium hydrogen carbonate is added until the fizzing due to the formation of carbon dioxide stops.

If 27.0 mL of 5.4 M sulfuric acid was spilled, what is the minimum mass of sodium hydrogen carbonate that must be added to the spill to neutralize the acid?

Answer 1

2 NaHCO(S) + H, SO4 (ag) > Na, Soy.coq) + 2 H, Om. + 2001g) n (NaHCO) = 2 x n CH₂SO4) n = number of moles number of moles - Molarity & Volume (h, so = C(H, sou) x UCH,sou) - = 5.4 M X 0.027L = 0.1458 moles n (Nako) = 2x 0.1458 moles = 0. 29 16 moles n (NaHCO) = mc NaHCO₃) M Nalle mo mass M = molar mass - m (NaHCO) = 0.2916 moles x 84.0079 mol = 24.499