A normal population has mean u=61 and standard deviation o=17. (a) What proportion of the population...

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Question

A normal population has mean u=61 and standard deviation o=17. (a) What proportion of the population is greater than 100? (b)

Answer 1

Answer #1

Given that l= 61, 0 = 17 (a) P(x = 100) 17 = P(Z > 2.29) = 10.0110 (6) P(x <82) 17 = P(Z < 1.24) = 10.8925]

Answer 2

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