Ans 5 :
Oxidation and reduction are the two chemical processes that increase or decrease the oxidation number of the element.
This happens by loosing or gaining electrons.
So here :
a) Oxidation : Loss of electron
b) Reduction : Gain of electron
Ans 6 :
a)
The balanced equation is given as :
C6H12O6 + 6O2 = 6CO2 + 6H2O
b)
Each mol glucose makes 6 mol CO2
so 10 mol glucose will make :
= 6 x 10 mol
= 60 mol carbon dioxide
c)
Mol glucose = mass / molar mass
= 360 g / 180 g/mol = 2 mol
Each mol glucose needs 6 mol oxygen
so 2 mol glucose will need : 2 x 6 mol = 12 mol oxygen
mass of oxygen = mol x molar mass
= 12 mol x 32 g/mol
= 528 g oxygen
question 5, 6 5. (10 pts) Helena compares oxidation with reduction. Match each term with the...
0/ 1 pts Question 2 During a certain titration, 35.0 mL of 0.175 M aqueous sulfuric acid was required to exactly neutralize 49.0 mL of sodium hydroxide. Determine the molarity of the base. H2SO4 (aq) + 2NaOH(aq) + 2 H2O (0) + Na2SO4 (aq) [balanced] 0.125 M 6.00 x 10 M 0.250 M 0.175 M 0.600 M 2ct Question 6 0/1 pts Calculate the pressure exerted by 5.12 grams of chlorine gas in a 850 mL sealed flask at 27.0°C....
Exam Name MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. 1) 1) One mole of any substance contains Avogadro's number of particles of that substance. What is the numerical value of Avogadro's number? A) 12.01 23 Avagrans t Male aton 6022 x1o atums B) 6.022 x 1023 C) 6.022 x 10-23 D) 1.661 x10-24 E) 1.00 x10-14 2) What is the mass of 4.00 moles of helium, the gas commonly used to fill...
Please complete for Tuesday, we will go through the questions and mark them in class. pg 156 - 4.23, 4.24, 4.26 pg 170 - 4.29, 4.31, pg 171-4.36 pg 175 - 4.59 pg 176- 4.74, 4.75, 4.80 pg 177-4.81, 4.82 pg 188- 5.1, 5.4, 5.5, 5.6, 5.11 - Using Table 5.1 pg 198-5.22, 5.25 pg 203 - 5.29 pg 206 - 5.37 pg 209 - 5.39 pg 2.14 5.61 pg 235-6.11, 6.14, 6.16 156 CHAPTER 4 Introduction to Organic Compounds...