Question

33) 33) EXTRA CREDIT: One mole of aluminum has a volume of 9.99 cm3. Using X-ray diffraction, each aluminum atom is found to occupy a cubic volume that is 0.263 nm on a side. Calculate the experimental value for Avogadro's number (N). AY 6.02 x 1023 BH,44 1023 5,49 % 1023 D) 3.80 x 1023 E) 1.82 1023
we got the wrong answer on exam

Answer 1

volume of Imole of AP = 0.99 cm? sicle ot Cube of 'All atom = 0.263 nm volume of Cube - a? volume of 'Al atou : a : (0-263 nmi Ivona 157cm. .: Volume et Al atau = (0.263x1ó?cm)? : (0-163 < (52)*.* = (0.26338 x 10² cm? : 0.01819 x1024 cms? = 0.01819 x 16 cm?. i mole = Avogadro No atau .: Alojadyo No : Volume ut i mole of A volume of letom of Al = 0.99 Shu 0.01819 x16?! Chap : 0.99_ x 10" 0.01819 22 : 54.425 X10 : $.44 XLO Avogadyo NO (N): 5.44 X102. This is the correy Aniwer.