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Q21 (15 points): A uniform rod of mass m 1.5 kg and length d- 2.0 m is supported by a pivot point P at its top and is free to rotate iın the vertical plane. A block of mass m2 0.8 kg is attached to the other end of the rod. The rod-block system is initially at rest, and a 1g bullet is fired horizontally into the rod through a point x 08 d below the pivot P Assume that the bullet lodges into the rod at the contact point and the rotational inertia of the rod about its center of mass is I- bullet 12311 block a) What is the rotational inertia of the rod-block-bullet system about the pivot P? Treat the block and the bullet as point particles. b) If the angular speed of the rod-block-bullet system about pivot P just after impact İs 0.2 rad/s, what is the bullets speed just before the impact? c) Find the energy lost in this collision

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Answer #1

0.8c1= 1.6m butlet 3lock rm b = 0.8kg ra tote netHa ÷x1.sx2. + o.ex4+1-x1.c2 = Pngn lar mementum Conser vedtion abtuut rol 6s

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