Question

MESSAGE MY INSTRUCTOR FULL SCREEN PRINTER VERSION BACK Chapter 11, Problem 060 t is fired into a 0.129 kg block attached to the end of a 0.242 m nonuniform rod of mass 0.728 kg. The block-rod-bulet system then rotates in the plane of the figure, about a fixed axis at A. The rotational inertia of the rod alone about A is 0.0 block-rod-bullet system about point A? (b) If the angular speed of the system about A just after impact is 5.60 rad/s, what is the bullet's speed just before impact? 488 kg-m2. Treat the block as a particle. (a) What then is the rotational inertia of the Rod Block Bullet Units (a) Number Units (b) Number

Answer 1

For part a) The moment of inertia of the system about A can be given by the sum total of moment of inertia due to each component of the system i.e. rotational inertia of system= rotational inertia (of rod + block+ bullet) about A.

Moment of inertia of a mass about a point at a distance d

= Md^{​​​​​2}

For part b) we will conserve the angular momentum of the system about A where, initial angular momentum= angular momentum of the bullet and final angular momentum= angular momentum of the rod block bullet system.

And hence find the velocity of the bullet