Question

RUCTOR FULL SCREEN PRINTER VERSION BACK NEXT Chapter 10, Problem 041 In the figure, two particles, each with mass m - 0.91 kg, are fastened to each other, and to a rotation axis at 0, by two thin rods, each with length d = 5.4 cm and mass M = 1.3 kg. The combination rotates around the rotation axis with angular speed w = 0.33 rad/s. Measured about o, what is the combination's (a) rotational Inertia and (b) kinetic energy? M Rotation axis (a) Number Unit (b) Number Unit 22 meV LINK TO TEXT LINK TO SAMPLE PROBLEM kev HEM LINK TO SAMPLE PROBLEM LINK TO SAMPLE PROBLEM VIDEO MINI-LECTURE Mev / m3 arn points based on the Point Potential Policy set by your instructor. By accessing this Question Assistance, you Gev

Answer 1

Answere a) given m=0.91kg; d = 5.4 cm; page1 M = 1.3kg ; w = 0.33 radls. Here the moment of inertia of the rods with respect to rotation aris at O is 1/2 x 2x Mx (2 L) - 13 x 2 MX4L the moment of inertia of the two ball about o is M XL"+mX(2L)" = mL + mx 4L = ml + 4 mL = 5ml I = I = ML + 5ML x 1.3 X 60.054) + 5 x 0.91 x(0.054) I- X13X 0002916 + 5x0.910.00 2916 - 2166 X - 3 10-00271G + 5x07 10:00 27/6 = 0.010083528 +0.01326 7 8 0.023351328 0.02335 kg.mn Scanned with CamScanner

page b) energy of rotation about the kinetic O is KE = 0.5X I XWr = 0.5 X 0.02335 (0.33) = 0.5 X 0.02335 x 0.1089 = 0.0012714 = 1.271 X 10-35 1. 271X II i Kinetic energy is. Scanned with CamScanner