2. Calculate the pH of a 0.10 M solution of aluminum chloride, which dissolves completely in...
Find the pH of a 0.008 M solution of an aluminum compound which dissolves completely to give the hydrated aluminum ion Al(H2O)3+6. Al(H2O)3+6(aq)+H2O(l)⇌H3O+(aq)+Al(H2O)5(OH)2+(aq), Ka=1.4×10−5 Report your answer with three significant figures. Find the pH of a 0.008 M solution of an aluminum compound which dissolves completely to give the hydrated aluminum ion Al(H2O)3+6. Al(H2O)3+6(aq)+H2O(l)⇌H3O+(aq)+Al(H2O)5(OH)2+(aq), Ka=1.4×10−5 Report your answer with three significant figures.
Calculate the pHof a 0.10 M solution of aluminum chloride, which dissolves completely in water to give the hydrated aluminumion [Al(H2O)6]3+in solution. Al 3 + (aq) + H 2 O (l) → [ Al(H 2 O) 6 ] 3 + (a q) [ Al(H 2 O) 6 ] 3 + (a q) + H 2 O (l) → [ Al(H 2 O) 5 OH ] 2 + (a q) + H 3 O + (aq ) Ka =...
When Ni(NO3)2 dissolves in water, the hexahydrate ion, Ni(H2O)62+, is formed. The pH of a 0.10 M aqueous solution of Ni(NO3)2 is 5.0. Thus, the acid ionization constant (Ka) for Ni(H2O)62+ ion must be
A pH 4.88 buffer which was prepared by dissolving 0.10 mol of benzoic acid (Ka=6.3x10-5) and 0.50 mol of sodium benzoate in sufficient pure water to form a 1.00 L solution. A 2.00 mL of 2.00 M HI solution was added to a 70.0 mL aliquot of this solution. a) What was the pH of the new 72.0 mL solution. b) If 0.01 mol A13+ is added to this new solution, will Al3+ ion be separated as Al(OH)3(s) (Ksp =...
2:12 al LTE Question 22 of 32 Submit A solution has a hydroxide-ion concentration of 0.18 M. What is its pH? A) 0.74 B) 13.26 C) 5.56 D) 0.18 2:12 al LTE Question 23 of 32 Submit Which one of the following correctly shows the equilibrium for the weak base quinoline, C.H.N? A) CEH,N (aq) + 2 H20 (1) = CH NH2* (aq) + 2 OH- (aq) B) C3H7N (aq) + H20 (1) = CH NH+ (aq) + OH- (aq)...
2nd part only the pH is correct. Metal ions in aqueous solutions are solvated, or hydrated, by water molecules. Typically this primary hydration sphere is composed of six water molecules. The hydrated metal ion acts as a weak acid, undergoing a stepwise hydrolysis in which it donates an Htion from its water ligands to the surrounding free water molecules. Shown is the hydrolysis of Al(H,0) (pKA = 4.85) in water. Al(H,0)(aq) + H20(1) - 1,0+ (aq) + Al( HO), OH...
The pH of a 0.10 M solution of hydrazoic acid, HN3, is 2.86. Calculate the Ka value for hydrazoic acid. A. 1.4 x 10-4 B. 1.9 x 10-5 C. 1.9 x 10-3 D. 1.4 x 10-5 E. 2.6 x 10-3
Netflix Twitter Stocks Canvas Mission Portal a Amazon Wells Fargo Hotmail MyMathlab Craiglist CC Question 2 4 pts The hydrated Al3+ ion in Al(NO3)3, is a weak acid in water. What are the products of its reaction with H2O? [Al(H20).13+(aq) + H2O(1) ? A) [AI(H20) OH)2+(aq) + H30* (aq) B) [Al(H2O).H]4+(aq) + OH(aq) C) (AI(H20)]3+(aq) + 2H2011) D) [Al(H20),OH)2+(aq) + H20*(aq) OD ОА Ос OB 4 pts Question 3
1) An Arrhenius acid is defined as a substance which: A) increases [H+] when placed in water C) decreases [H+] when placed in water B) acts as proton acceptor in any system D) acts as proton donor in any system 2) Which of the following is a correct balanced equation for the neutralization reaction that occurs between Al(OH)3 and HCl(aq)? A) Al(OH)3 + HCl(aq) → AICI3 + H20 B) Al(OH)3 + 3 HCI (aq) → AICI3 + H+ + OH-...
10. For an aqueous solution labeled "0.10 M potassium bromide," A) the pH is greater than 7. B) the pH = 13. D) the pH is less than 7. E) the pH = 7. C) the pH = 1. 11. For a 0.10 M solution of a weak acid, HA, with pKa = 6, which of the following is true? A) [HA] =[A-] B) [HA] does not equal [H3O+] C) [HA] =[H3O] D) [HA] = K E) [HA] = 0...