I was not able to get the correct answer to the following problem: "A proton is at the origin and an electron is at the point x = 0.42 nm , y = 0.30 nm . Part A Find the electric force on the proton." I came up with the answer: Fx = 7.7*10^(-10), Fy = 5.53*10^(-10).
I was not able to get the correct answer to the following problem: "A proton is...
A proton is at the origin and an electron is at the point x = 0.45 nm , y = 0.36 nm . Find the electric force on the proton. Express your answer using two significant figures. Enter your answers numerically separated by a comma. Fx, Fy= N
Constants Periodic Table Part A A proton is at the origin and an electron is at the point nm,y-0.39 m 0.37 Find the x- and y-components of the electric force on the proton Express your answer using two significant figures. Enter your answers numerically separated by a comma. Submit Provide Feedback Next >
Can you still work out part A? I need another view of working that problem out Thanks An electron and a proton are each moving at 765 km/s in perpendicular paths as shown in (Figure 1). Electron 5.00 nm Proton -X 4.00 nm Part A At the instant when they are at the positions shown, find the magnitude of the total magnetic field they produce at the origin. Express your answer with the appropriate units. B = 1.25 mT Submit...
Part In a simple model of the hydrogen atom, the electron moves in a circular orbit of radius 0.053 nm around a stationary proton. What is the magnitude of the electron's acceleration? Part C Particle A has a charge of 3.4 nC and is at the origin. Particle B has a charge of -8.2 nC and is at (r, y) (3.0 cm, 4.0 cm). F is the force particle A exerts on particle B. Calculate the values of Fx. Fy,...
can you do Part B with the new q2 value. i know the correct answer but can you show how you get it bc i keep getting 20.7 degrees below the axis. thanks <Homework-1 Practice Problem 17.04 - Enhanced - with Feedback 2 of 6 • Comple Review I Constant Previous Answers Now we will consider a two-dimensional arrangement of charges (Figure 1). A point charge 2.0 C is located on the positive y axis at y=0.30 m, and an...
1) A point charge q = -0.49 nC is fixed at the origin. 2) Where must a proton be placed in order for the electric force acting on it to be exactly opposite to its weight? (Let the y axis be vertical and the x axis be horizontal.) - ans: I know the proton in question needs to be placed below q 3) Second part of the question is asking to express the answer to 2 significant figs, and have...
Where must a proton be placed in order for the electric force acting on it to be exactly opposite to its weight? (Let the y axis be vertical and the z axis be horizontal.) Review A point charge q-0.54 nC is fixed at the origin above the q below the q Correct Part B Express your answer using two significant figures. km
Need help with how you get Part B. How do you find m in the equation a=qe/m as well? Please provide answer and work. Thanks! If correct will give a thumbs up A 2.02 x 10-9 C charge has coordinates x-0, y--2.00; a 2.91 x 10-9 C charge has coordinates x-3.00, y-0; and a -4.60 10-9 C charge has coordinates x 3.00, y-4.00, where all distances are in cm. Determine magnitude and direction for the electric field at the origin...
this is the 3rd time posting this question, please get the directions correct. A 2.08. 109 C charge has coordinates x-0,y- 2.00; a 3.21 10-9 C charge has coordinates x- 3.00, y-0; and a 4.75. 10-9 C charge has coordinates x- 3.00, y - 4.00, where all distances are in cm. Determine magnitude and direction for the electric field at the origin and the instantaneous acceleration of a proton placed at the origin. (a) Determine the magnitude and direction for...
A point charge q = -0.30 nC is fixed at the origin. Part A Where must a proton be placed in order for the electric force acting on it to be exactly opposite to its weight? (Let the y axis be vertical and the x axis be horizontal.) Where must a proton be placed in order for the electric force acting on it to be exactly opposite to its weight? (Let the axis be vertical and the axis be horizontal.)...