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A point charge q = -0.30 nC is fixed at the origin. Part A Where must...

A point charge q = -0.30 nC is fixed at the origin. Part A Where must a proton be placed in order for the electric force acting on it to be exactly opposite to its weight? (Let the y axis be vertical and the x axis be horizontal.) Where must a proton be placed in order for the electric force acting on it to be exactly opposite to its weight? (Let the axis be vertical and the axis be horizontal.) below the q above the q. Part B Express your answer using two significant figures. r =?

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Here we have equation for force acting Weight is given by formula Equating both equations we get r-distan ce between charges

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