Question

Tarzan and Jane have an argument and aimultaneoualy walk away from where they were atanding. Tarzan atompa off for 42 metera in a direction 50 weat of north and then atopa. Jane walka 24 metera in a direction 80° south of eaat and then atopa. After aome aulking, Tarzan realizea he waa at fault and turna to face Jane. 9. a. Draw a veotor addition diagram for thia aituation to some relative scale. b. How far must Tarzan walk in a straight line to get to Jane? Sohve thia queation using vector addition and vector componenta. Show all atepa. Anawer: 62.3 m c. In what direotion muat he walk? Anawer: 54.3° south of eaat.

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Answer #1

The situation given in the problem is shown below.

  N: North 42 m、 50 x E : East W : West 80° 24 m S: South

Figure : 1

The path of Tarzan is shown by vector A ( here, the direction of Tarzan is shown towards the Jane )and the path of Jane is shown by vector B .

(a) The vector addition diagram is shown below :

  N: North 42 m 50 x E : East W : West 800 24 m S: South

  Figure : 2

This diagram is just for better understanding.

Here vector R is showing the resultant vector.

or,   R = A + B

(b)  From figure : 1 , we can write

A - 42cos 50° (-)42 sin 50 i

or,   A 32.174 i -26.997 j

And,   B = 24 cos 80° і + 24 sin 80° (-j)

or,   В 4.167 i-23.635

So,   → R = + B = (32. 174 i-26.997 j) + (4.167 i-23.635 j)

or,   R 36.34150.632

So, the magnitude of R is

  R- R- V(36.341)2 +(-50.632)2V1320.668 + 2563.599

384.267- 62.3m

Hence, Tarzan must have to walk 62.3 m in a straight line to get Jane.

(c) The direction or the angle made by resultant vector R with positive x - axis can be calculated as

θ tan-1 (-50.632 tan-1(-1.39) =-54.33° 36.341

hence, he should walk in a direction 54.30 south of east .

For any doubt please comment and please give an up vote. Thank you.

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