please be clear in drawings to show where areas are coming from and what theyre pointing to
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please be clear in drawings to show where areas are coming from and
what theyre pointing...
Draw curved arrows to show the movement of electrons in this step of the mechanism.
Electrophilic addition of bromine, Br-, to alkenes yields a 1,2-dibromoalkane. The reaction proceeds through a cyclic intermediate known as a bromonium ion. The reaction occurs in an anhydrous solvent such as CH2Cl2 In the second step of the reaction, bromide is the nucleophile and attacks at one of the carbons of the bromonium ion to yield the product. Due to steric clashes, the bromide ion always attacks the carbon from the opposite face of the bromonium ion so that a product...
Draw curved arrows to show the movement of electrons in this step of the mechanism.
Electrophilic addition of bromine, Br2, to alkenes yields a 1,2-dibromoalkane. The reaction proceeds through a cyclic intermediate known as a bromonium ion. The reaction occurs in an anhydrous solvent such as CH2Cl2 In the second step of the reaction, bromide is the nucleophile and attacks at one of the carbons of the bromonium ion to yield the product. Due to steric clashes, the bromide ion always attacks the carbon from the opposite face of the bromonium ion so that a product...
2 problems (Review Topical (References Br н,слен . CH2Cl2 Electrophilic addition of bromine, Bry, to alkenes...
2 problems
(Review Topical (References Br н,слен . CH2Cl2 Electrophilic addition of bromine, Bry, to alkenes yields a 1,2 dibromoalkane. The reaction proceeds through a cyclic intermediate known as a bromonium ion. The reaction occurs in an anhydrous solvent such as CH CI In the second step of the reaction, bromide is the nucleophile and attacks at one of the carbons of the bromonium ion to yield the product Due to stenc clashes, the bromide ion always attacks the carbon...
Electrophilic addition of bromine, Br2, to alkenes yields a 1,2-dibromoalkane
Electrophilic addition of bromine, Br2, to alkenes yields a 1,2-dibromoalkane. The reaction proceeds through a cyclic intermediate known as a bromonium ion. The reaction occurs in an anhydrous solvent such as CH2Cl2In the second step of the reaction, bromide is the nucleophile and attacks at one of the carbons of the bromonium ion to yield the product. Due to steric clashes, the bromide ion always attacks the carbon from the opposite face of the bromonium ioa so that a product...
Draw curved arrows to show the movement of electrons in this step of the mechanism.
Electrophilic addition of hypohalous acids to alkenes yields a 1,2-haloalcohol called a halohydrin. Halohydrin formation, however, does not result from the addition of HO-Br, for example. Instead the addition is done indirectly by reaction of the alkene with Br2 in the presence of water. The reaction also works with Cl2 to give chlorohydrins instead of bromohydrins. The reaction proceeds through a cyclic intermediate known as a bromonium ion. In the second step of the reaction, water is the nucleophile and reacts with the...
2 problems REVIEW Topics [References) CH HC OCH Br2 CH3 B H3C CH,OH H₂C CH₂ Electrophilic...
2 problems
REVIEW Topics [References) CH HC OCH Br2 CH3 B H3C CH,OH H₂C CH₂ Electrophilic addition of hypohalous acids to alkenes yields a 1,2-haloalcohol called a halohydrin. Halohydrin formation, however, does not result from the addition of HOBr, for example. Instead the addition is done indirectly by reaction of the alkene with Br, in the presence of water. The reaction also works with Cl2 to give chlorohydrins instead of bromohydrins. The reaction proceeds through a cyclic intermediate known as...
halogenation of alkenes 1, 2. d a l . The reaction proceeds through a cyclic intermediate...
halogenation of alkenes
1, 2. d a l . The reaction proceeds through a cyclic intermediate known as a brom m ion. The Electrophilic addition of bromin, Bry, toalkenes vields reaction occur in n ons solvent such as CH CH. In the second step of the action beemide is the meets and attacks one of the bons of the roman bromide away s the carbon from the opposite face of the be s t product with to vield the peodet....
can question 3 a-b be answered please 3. Fill in the curved arrows for this mechanism...
can question 3 a-b be answered please
3. Fill in the curved arrows for this mechanism of the bromine addition to alkenes. Br Br+ Br Br Br-Br CH Br relative stereochemistry mixture of diastereomers a. The intermediate in the reaction is a cyclic bromonium ion. Circle it. b. This reaction is described as an anti-addition. Look at the product-what does that mean?
CH3 CH3 1. Hg(OAC), H20 2. NaBH НО, І CH3 CH, Hoc H₃C/ Acid-catalyzed addition of...
CH3 CH3 1. Hg(OAC), H20 2. NaBH НО, І CH3 CH, Hoc H₃C/ Acid-catalyzed addition of water to an alkene yields an alcohol with Markovnikov regiochemistry. The electrophilic H adds to the sp carbon with the most hydrogens to yield the most stable carbocation intermediate, which then adds water to give the product alcohol. Because a carbocation intermediate is formed, rearrangements can occur prior to the addition of water. To avoid the possibility of rearrangement and still give a Markovnikov...
Tulung ate n illud aludke place in a single step. In the Sn2 reaction, the nucleophile...
Tulung ate n illud aludke place in a single step. In the Sn2 reaction, the nucleophile attacks the a-carbon from the backside and displaces the leaving group with an inversion of configuration occurring at the carbon. In the E2 elimination reaction, strong base removes an acidic hydrogen from the B-carbon and an alkene is formed as the leaving group is expelled from the a-carbon. This elimination follows Zaitsey's rule whereby the more substituted alkene is generally formed. In E2 elimination,...
2 problems
(Review Topical (References Br н,слен . CH2Cl2 Electrophilic addition of bromine, Bry, to alkenes yields a 1,2 dibromoalkane. The reaction proceeds through a cyclic intermediate known as a bromonium ion. The reaction occurs in an anhydrous solvent such as CH CI In the second step of the reaction, bromide is the nucleophile and attacks at one of the carbons of the bromonium ion to yield the product Due to stenc clashes, the bromide ion always attacks the carbon...
2 problems
REVIEW Topics [References) CH HC OCH Br2 CH3 B H3C CH,OH H₂C CH₂ Electrophilic addition of hypohalous acids to alkenes yields a 1,2-haloalcohol called a halohydrin. Halohydrin formation, however, does not result from the addition of HOBr, for example. Instead the addition is done indirectly by reaction of the alkene with Br, in the presence of water. The reaction also works with Cl2 to give chlorohydrins instead of bromohydrins. The reaction proceeds through a cyclic intermediate known as...
halogenation of alkenes
1, 2. d a l . The reaction proceeds through a cyclic intermediate known as a brom m ion. The Electrophilic addition of bromin, Bry, toalkenes vields reaction occur in n ons solvent such as CH CH. In the second step of the action beemide is the meets and attacks one of the bons of the roman bromide away s the carbon from the opposite face of the be s t product with to vield the peodet....
can question 3 a-b be answered please
3. Fill in the curved arrows for this mechanism of the bromine addition to alkenes. Br Br+ Br Br Br-Br CH Br relative stereochemistry mixture of diastereomers a. The intermediate in the reaction is a cyclic bromonium ion. Circle it. b. This reaction is described as an anti-addition. Look at the product-what does that mean?
CH3 CH3 1. Hg(OAC), H20 2. NaBH НО, І CH3 CH, Hoc H₃C/ Acid-catalyzed addition of water to an alkene yields an alcohol with Markovnikov regiochemistry. The electrophilic H adds to the sp carbon with the most hydrogens to yield the most stable carbocation intermediate, which then adds water to give the product alcohol. Because a carbocation intermediate is formed, rearrangements can occur prior to the addition of water. To avoid the possibility of rearrangement and still give a Markovnikov...
Tulung ate n illud aludke place in a single step. In the Sn2 reaction, the nucleophile attacks the a-carbon from the backside and displaces the leaving group with an inversion of configuration occurring at the carbon. In the E2 elimination reaction, strong base removes an acidic hydrogen from the B-carbon and an alkene is formed as the leaving group is expelled from the a-carbon. This elimination follows Zaitsey's rule whereby the more substituted alkene is generally formed. In E2 elimination,...
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