Homework Answers
Ques No 8:
From the given graph, it can be seen that from 0 - 2h, the position- time graph is haveing a constant slope; i.e. the velocity of the particle is constant between t = 0 h to t =1 h and is equal to ( 30 km / 2 h ) = 15 km /h.
Option (iii) is the correct choice (Ans)
6. An object moves along the x-axis. The graph shows its position x as a function...
6. An object moves along the x-axis. The graph shows its position x as a function of time t. Find ( point) the average velocity of the object from points B to C x (m) 10 8 6 2 t (s) 0 1 23 4 5 6 1.8 m/s 1.0 m/s 1.5 m/s 0.67 m/s 10. A person is walking briskly in a straight line. The figure shows a graph of the person's position (1 point) x as a function...
Find the instantaneous acceleration at t = 13 s. v (m/s) 8 6 4 2 0...
Find the instantaneous acceleration at t = 13 s. v (m/s) 8 6 4 2 0 t(s) 5 10 15 20 -2. 0.8 m/s^2 -0.8 m/s^2 1.6 m/s^2 O m/s^2
must be in w ond, (c) the t one answer ) m/s? (a) 0 (b) 10...
must be in w ond, (c) the t one answer ) m/s? (a) 0 (b) 10 m/s (c) -10 m/s (d) 10 (e) 14.1 m/s utunng tne situation with the greatest resultant magni- of th tude first. If the total displacement is the same size in 1. Vect will qua two situations, give those letters equal ranks. 12. As 30 su Figure 003.4 5. The magnitude of vector A is 8 km, and the magnitude of B is 6 km....
Problem 2.02 1 of 26 A person is walking briskly in a straight line, which we...
Problem 2.02 1 of 26 A person is walking briskly in a straight line, which we shall call the x axis. The figure shows a graph of the person's position x along this axis as a function of time t.(Figure 1) What is the person's displacement between \texttip{t{t1} = 2.00 {\rm s} and \texttip{t}{{2} = 11.0 {\rm s} ? d = {\rm m} Submit Request Answer Part B What is the person's displacement between \texttip{t/t3} = 3.00 {\rm s} and...
5. What is the acceleration of the object in the graph? point) (m/s) 14- 12 10...
5. What is the acceleration of the object in the graph? point) (m/s) 14- 12 10 8 6 4 2 0 2 4 68 10 12 14 16 18 t(S) O-0.8 m/s O 1.25 m/s -1.25 m/s2 0-0.4 m/s 9. In the equatiox2+2a, (x-Xo), what do the terms vor , and xo stand for1 point,) respectively? O velocity at position x, velocity at time t = 0, position x, and position at time t = 0 velocity at position r,...
Pleaseeee question 6,7,8,9 Pleaseeeee he bottom, as shown. If her speed at the bottom of the hill (point B) is 19 m/s, what is her speed at point A? a. 12 m/s b. 13 m/s c. 14 m/s 40 30 m d. 15 m/s...
Pleaseeee question 6,7,8,9 Pleaseeeee
he bottom, as shown. If her speed at the bottom of the hill (point B) is 19 m/s, what is her speed at point A? a. 12 m/s b. 13 m/s c. 14 m/s 40 30 m d. 15 m/s e16 m/s 7) A 12-cm diameter optical disk start from rest and reaches 5,500 RPM in 0.501 seconds. If the disk has a mass of 15.3 g, what is magnitude of torque applied by disk drive...
x (m) А В 2 1 1(s) 1.0 2.0 3.0 / 4.0 1. If the phase...
x (m) А В 2 1 1(s) 1.0 2.0 3.0 / 4.0 1. If the phase velocity or propagation of wave B is 0.50m / s to the right, the wave propagation equation is: O a. y(xt)-1.5 Cos[(T m-1)x - (2 841) O b. y(x,t) = 3.5 Cos[(2n m`-1)x - (TU S-1)] O c.y(xt) = 2.5 Sin [(T m-1)x - (2 s^-1)] O d. y(x,t) = 3.5 Cos[(21 m^-1)x + (nt 51-1)] 2. Find the phase velocity or propagation of...
1. The point P(4. 8) lies on the curve y-(6-x), Suppose Q is the point (x,1 + (6-x)'). a. Find th...
can
you answer two of the questions in the phot please.
1. The point P(4. 8) lies on the curve y-(6-x), Suppose Q is the point (x,1 + (6-x)'). a. Find the slope of the secant line PO for the following values of x. 3. 3.99 4. 3.999 6. 4.1 7. 4.01 8. 4.001 the curve at P b. Use your results from part a to make a guess of the slope of the line tangent to c. Use your...
Velocity Vs. Time 10 8 6 Velocity , v, (m/s) 0 2 4 6 8 10...
Velocity Vs. Time 10 8 6 Velocity , v, (m/s) 0 2 4 6 8 10 12 14 -4 -6 -8 Time, t, (s) a) Determine the average velocity of the object between 4.0 and 8.0 s. Over what time interval(s), if any, is the object decelerating (slowing down)? b) At what time(s), if any, does the object remain at rest?
For the following velocity graph, velocity is in m/s and time is in s. For the...
For the following velocity graph, velocity is in m/s and time is in s. For the interval t 2s to t = 5s, find (a)[4 pts] the average acceleration, and (b)4 pts] the displacement Aæ. t 5 2 4 1 For the following described motion, draw a position-time, a velocity-time, and an acceleration-time graph on the grids provided: 1. Standing still at the 0.6 meter position for 1 second. 2. Walking away from the detector speeding up slowly and steadily...
6. An object moves along the x-axis. The graph shows its position x as a function of time t. Find ( point) the average velocity of the object from points B to C x (m) 10 8 6 2 t (s) 0 1 23 4 5 6 1.8 m/s 1.0 m/s 1.5 m/s 0.67 m/s 10. A person is walking briskly in a straight line. The figure shows a graph of the person's position (1 point) x as a function...
Find the instantaneous acceleration at t = 13 s. v (m/s) 8 6 4 2 0 t(s) 5 10 15 20 -2. 0.8 m/s^2 -0.8 m/s^2 1.6 m/s^2 O m/s^2
must be in w ond, (c) the t one answer ) m/s? (a) 0 (b) 10 m/s (c) -10 m/s (d) 10 (e) 14.1 m/s utunng tne situation with the greatest resultant magni- of th tude first. If the total displacement is the same size in 1. Vect will qua two situations, give those letters equal ranks. 12. As 30 su Figure 003.4 5. The magnitude of vector A is 8 km, and the magnitude of B is 6 km....
Problem 2.02 1 of 26 A person is walking briskly in a straight line, which we shall call the x axis. The figure shows a graph of the person's position x along this axis as a function of time t.(Figure 1) What is the person's displacement between \texttip{t{t1} = 2.00 {\rm s} and \texttip{t}{{2} = 11.0 {\rm s} ? d = {\rm m} Submit Request Answer Part B What is the person's displacement between \texttip{t/t3} = 3.00 {\rm s} and...
5. What is the acceleration of the object in the graph? point) (m/s) 14- 12 10 8 6 4 2 0 2 4 68 10 12 14 16 18 t(S) O-0.8 m/s O 1.25 m/s -1.25 m/s2 0-0.4 m/s 9. In the equatiox2+2a, (x-Xo), what do the terms vor , and xo stand for1 point,) respectively? O velocity at position x, velocity at time t = 0, position x, and position at time t = 0 velocity at position r,...
Pleaseeee question 6,7,8,9 Pleaseeeee
he bottom, as shown. If her speed at the bottom of the hill (point B) is 19 m/s, what is her speed at point A? a. 12 m/s b. 13 m/s c. 14 m/s 40 30 m d. 15 m/s e16 m/s 7) A 12-cm diameter optical disk start from rest and reaches 5,500 RPM in 0.501 seconds. If the disk has a mass of 15.3 g, what is magnitude of torque applied by disk drive...
x (m) А В 2 1 1(s) 1.0 2.0 3.0 / 4.0 1. If the phase velocity or propagation of wave B is 0.50m / s to the right, the wave propagation equation is: O a. y(xt)-1.5 Cos[(T m-1)x - (2 841) O b. y(x,t) = 3.5 Cos[(2n m`-1)x - (TU S-1)] O c.y(xt) = 2.5 Sin [(T m-1)x - (2 s^-1)] O d. y(x,t) = 3.5 Cos[(21 m^-1)x + (nt 51-1)] 2. Find the phase velocity or propagation of...
can
you answer two of the questions in the phot please.
1. The point P(4. 8) lies on the curve y-(6-x), Suppose Q is the point (x,1 + (6-x)'). a. Find the slope of the secant line PO for the following values of x. 3. 3.99 4. 3.999 6. 4.1 7. 4.01 8. 4.001 the curve at P b. Use your results from part a to make a guess of the slope of the line tangent to c. Use your...
Velocity Vs. Time 10 8 6 Velocity , v, (m/s) 0 2 4 6 8 10 12 14 -4 -6 -8 Time, t, (s) a) Determine the average velocity of the object between 4.0 and 8.0 s. Over what time interval(s), if any, is the object decelerating (slowing down)? b) At what time(s), if any, does the object remain at rest?
For the following velocity graph, velocity is in m/s and time is in s. For the interval t 2s to t = 5s, find (a)[4 pts] the average acceleration, and (b)4 pts] the displacement Aæ. t 5 2 4 1 For the following described motion, draw a position-time, a velocity-time, and an acceleration-time graph on the grids provided: 1. Standing still at the 0.6 meter position for 1 second. 2. Walking away from the detector speeding up slowly and steadily...
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