A NaOH solution is standardized using axalic acid, C2H2O4 (90g/mol) according to the following balanced equation: H2C2O4 (aq) + 2NaOH (aq) -> Na2C2O4 (aq) + 2H2O (l)
If 0.8986g of oxalic acid requires 63.92mL of NaOH, what is the NaOH concentration?
Balanced chemical equation is:
H2C2O4 (aq) + 2NaOH (aq) -> Na2C2O4 (aq) + 2H2O (l)
Molar mass of H2C2O4,
MM = 2*MM(H) + 2*MM(C) + 4*MM(O)
= 2*1.008 + 2*12.01 + 4*16.0
= 90.036 g/mol
mass(H2C2O4)= 0.8986 g
use:
number of mol of H2C2O4,
n = mass of H2C2O4/molar mass of H2C2O4
=(0.8986 g)/(90.04 g/mol)
= 9.98*10^-3 mol
According to balanced equation
mol of NaOH reacted = (2/1)* moles of H2C2O4
= (2/1)*9.98*10^-3
= 1.996*10^-2 mol
This is number of moles of NaOH
volume , V = 63.92 mL
= 6.392*10^-2 L
use:
Molarity,
M = number of mol / volume in L
= 1.996*10^-2/6.392*10^-2
= 0.3123 M
Answer: 0.312 M
A NaOH solution is standardized using axalic acid, C2H2O4 (90g/mol) according to the following balanced equation:...
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