In a standardization process, 0.2161 g of oxalic acid (H2C2O4 : MM 90.04 g/mol) was neutralized...
In a standardization process, 0.2161 g of oxalic acid (H2C2O4 : MM 90.04 g/mol) was neutralized with 32.0 mL NaOH. Find the molarity of NaOH. H2C2O4 + 2NaOH à Na2C2O4 + 2H2O
A: 0.250 M
B: 0.100 M
C: 0.150 M
D: 0.300 M
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In a standardization process, 0.2161 g of oxalic acid (H2C2O4 :
MM 90.04 g/mol) was neutralized...
A NaOH solution is standardized using axalic acid, C2H2O4 (90g/mol) according to the following balanced equation:...
A NaOH solution is standardized using axalic acid, C2H2O4 (90g/mol) according to the following balanced equation: H2C2O4 (aq) + 2NaOH (aq) -> Na2C2O4 (aq) + 2H2O (l) If 0.8986g of oxalic acid requires 63.92mL of NaOH, what is the NaOH concentration?
Trial one Trial two Trial three Volume of oxalic acid (mL) 10.1 mL 10.2 mL 10.1...
Trial one Trial two Trial three Volume of oxalic acid (mL) 10.1 mL 10.2 mL 10.1 mL Moles of oxalic acid (moles) Initial volume of NaOH (mL) 18.7 mL 26.5 mL 34.6 mL Final volume of NaOH (mL) 26.5 mL 34.6 mL 42.6 mL Delivered volume of NaOH (moles) 7.8 mL 8.1 mL 8 mL Moles of NaOH (moles) Molarity of NaOH (M) Average Molarity NaOH (M) Concentration of oxalic acid (M) = 0.2567 Trial one Trial two Trial three...
6. Oxalic acid H2C2O4 is a diprotic acid and can be used, in dilute form, as...
6. Oxalic acid H2C2O4 is a diprotic acid and can be used, in
dilute form, as wood bleach. pKa1 = 1.237 and pKa2=4.187
A. How many milliliters of 0.0500 M NaOH would be required to
completely neutralize 10.0 mL of 0.100 M H2C2O4? (5 pts)
B. Estimate the pH at the first equivalence point of the
titration. (6 pts)
C. What is the pH at the second equivalence point of the
titration. (8 pts)
Please help with work shown, especially...
What is the mass percent of carbon (12.01 g/mol) in oxalic acid, H2C2O4 (90.0349 g/mol)?
What is the mass percent of carbon (12.01 g/mol) in oxalic acid, H2C2O4 (90.0349 g/mol)?
A mixture of acetic acid (CH3 CO2H monoprotic) and oxalic acid (H2C2O4; diprotic) requires 27.15 mL...
A mixture of acetic acid (CH3 CO2H monoprotic) and oxalic acid (H2C2O4; diprotic) requires 27.15 mL of 0.100 M NaOH to neutralize it. When an identical amount of the mixture is titrated, 15.05 mL of 2.68x10-2 M KMnO, is needed for complete reaction.
Data Table 1 Mass of flask and oxalic acid (g) 117.43 Mass of empty flask (g)...
Data Table 1 Mass of flask and oxalic acid (g) 117.43 Mass of empty flask (g) 116.93 Mass of oxalic acid (g) 0.5 Moles of oxalic acid (mol) Final volume of NaOH (mL) 17 Initial volume of NaOH (mL) 5 Volume of NaOH used (mL) 12 Moles of NaOH (mol) Molarity of NaOH (M) Data Table 2 Mass of flask and vinegar (g) 126.61 Mass of empty flask (g) 121.63 Mass of vinegar (g) 4.98 Final volume of NaOH (mL)...
a) Write the reaction for the neutralization oxalic acid (H2C2O4) with sodium hydroxide (NaOH). Note oxalic...
a) Write the reaction for the neutralization oxalic acid (H2C2O4) with sodium hydroxide (NaOH). Note oxalic acid is diprotic (like sulfuric acid). b) A 0.1187 g sample of an unknown, diprotic solid acid is dissolved in water. 26.36 mL of 0.1000 M sodium hydroxide is used to reach the equivalence point. How many moles of sodium hydroxide were reacted? How many moles of acid reacted? What is the molecular weight of the acid?
A solution is prepared by dissolving 0.5892 g oxalic acid (H2C2O4) in enough water to make...
A solution is prepared by dissolving 0.5892 g oxalic acid (H2C2O4) in enough water to make 100.0 mL of solution. A 10.00-mL aliquot (portion) of this solution is then diluted to a final volume of 250.0 mL. What is the final molarity of the diluted oxalic acid solution? I do not know if the answer of 0.00187 or 1.87 x 10^ -3 is correct. It is incorrect in my perspective, so i do not expect that answer, if you think...
Calculate the Amount of HCl Neutralized by Titration (mol) Parts 1 & 2, Standardization of NaOH and HC Record the mclarities from standardization or from reagent bottles of the HCl and the NaOH....
Calculate the Amount of HCl Neutralized by Titration (mol)
Parts 1 & 2, Standardization of NaOH and HC Record the mclarities from standardization or from reagent bottles of the HCl and the NaOH. molarity of HCI1.0780 molarity of NaOH 4851 Your value is acceptable. M Your value is acceptable. M Part 3. Determination of the Amount of Acid Neutralized by an Antacid Tablet Record the data from your titration in Table 1. (Enter NONE in any unused answer blanks.) Table...
A student titrated 15.0 mL of acetic acid acid, HC2H302 ( Molar mass= 60 g/mol) solution...
A student titrated 15.0 mL of acetic acid acid, HC2H302 ( Molar mass= 60 g/mol) solution with 25.0 mL of a 0.100 M NaOH solution The Molarity(mol/L) of HC2H302 required for complete titration is? HC2H302 + NaOH - NaC2H302 + H20 A) 0.0250 M B) 0.250 M C) 2.5M D) 0.0167M E) 0.167 mol
6. Oxalic acid H2C2O4 is a diprotic acid and can be used, in
dilute form, as wood bleach. pKa1 = 1.237 and pKa2=4.187
A. How many milliliters of 0.0500 M NaOH would be required to
completely neutralize 10.0 mL of 0.100 M H2C2O4? (5 pts)
B. Estimate the pH at the first equivalence point of the
titration. (6 pts)
C. What is the pH at the second equivalence point of the
titration. (8 pts)
Please help with work shown, especially...
A mixture of acetic acid (CH3 CO2H monoprotic) and oxalic acid (H2C2O4; diprotic) requires 27.15 mL of 0.100 M NaOH to neutralize it. When an identical amount of the mixture is titrated, 15.05 mL of 2.68x10-2 M KMnO, is needed for complete reaction.
Calculate the Amount of HCl Neutralized by Titration (mol)
Parts 1 & 2, Standardization of NaOH and HC Record the mclarities from standardization or from reagent bottles of the HCl and the NaOH. molarity of HCI1.0780 molarity of NaOH 4851 Your value is acceptable. M Your value is acceptable. M Part 3. Determination of the Amount of Acid Neutralized by an Antacid Tablet Record the data from your titration in Table 1. (Enter NONE in any unused answer blanks.) Table...
A student titrated 15.0 mL of acetic acid acid, HC2H302 ( Molar mass= 60 g/mol) solution with 25.0 mL of a 0.100 M NaOH solution The Molarity(mol/L) of HC2H302 required for complete titration is? HC2H302 + NaOH - NaC2H302 + H20 A) 0.0250 M B) 0.250 M C) 2.5M D) 0.0167M E) 0.167 mol
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