∆E = ∆H + ∆F -∆G
A process is carried out such that AH = -5.9 kJmol1,AG = 23.7 kJ mol-1 and...
Part B Find AH; for BF3 (g) from the given table. Substance AH kJ/mol 565.0 o 79.38 B(g) B(s) F(g) F2(g) BF3(8) BC1: (g) B,H6(8) B2O3(g) - 1136.0 -403.8 36.4 - 1273.5 Express your answer using one decimal place. IVO AQ – Oo ? AH; - kJ/mol Submit Request Answer
Problem 7.7 The melting of sold ice to give liquid water has AH-144 kcal/ mol(+602 kJ/mol and AS -5.25 cal/mol.K) (220 J/(mol )) What is the value of AG for the melting process at the following temperatures? SC (265) Express your answer using two decimal places. 10 A4 OE? AG- kcal/mol kJ/mol Subm Beguest Answer Part B Is the melting spontaneous or nonspontaneous at -10° 283 K spontaneous nospontaneous in equilibrium Submit Neuts or nonpontaneous at 0273 )
Part A AH = -90 kJ. ASX = - 149 J/K T = 293 K Express your answer using two significant figures. AEDRO? AG. Submit Request Answer Part B AH = -90 kJ. AS. = -149 J/K T = 755K Express your answer using two significant figures. 90 ALO R ?
Part G Calculate AH for the following reaction: CH3OH(1) +O2(g) + HCOH(1) +H2O(1) Express the enthalpy in kilojoules to one decimal place. AC O O ? AH = Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining Part 1 Calculate AS for the following reaction: CHOH(1) +O2(g) + HCO-H1) +H2O(1) Express the entropy in joules per kelvin to one decimal place. IVO AED ROO? J/K AS = Submit Request Answer Part 1 From the values of AH°...
Using provided data, determine AG* (in kJ) for the following reaction. 2036) ++3026) AH,(kJ/mol) S /mol) Ozle) 205.0 Ole) 143 238.82 Question 11 2 pts Use the provided information to determine the equilibrium constant at 298 K for the reaction given 2NO26) N204(8) 4 AH® (kJ/mol) 5° (J/molk) NO2(g) 33.2 239.9 N2048) 9.16 304.3 Equilibrium Constant - (Select) x 10 (Select)
Part AH X = 90 kJ , ASrxn = – 149 J/K , T = 293 K Express your answer using three significant figures. 10 AJO O O ? AG = Submit Request Answer Part D AHX = - 90 kJ, A Srxn = 149 J/K, T = 401 K Express your answer using three significant figures. IVO AQ R o o ?
1. Calculate AS, AH and AG for the following spontaneous (irreversible) process (with 3.0 mol of water at 1 atm). H2O (liquid, -15 °C) → H2O (solid, -15 °C) It is known that the heat of fusion of water at 0 °C is 1436 cal/mol; the heat capacity of liquid water is 18.0 cal/mol, the heat of capacity of ice is 8.7 cal/mol. H2O (liquid, -10 °C) → H2O (liquid, 0 °C). HO (liquid, -15°C) H.O(solid, -15°C) Process (1) Process...
AG°= AH-TAS AG=AGº+RTinQ where R=8.314 J/mol K 1. Calculate AGº for the following reaction at 25 °C if AH°= -1854 kJ/mol; AS°= -236 J/mol K CH-COCH3(g) + 402(g) → 3C02(g) + 3H2O(1) 2. NH.NO, dissolving in water is a spontaneous process. As it dissolves, the temperature of the solution decreases. Based on this, what must the signs (positive or negative) of AG, AH, and AS be?
Part A Use the information provided to determine AHºn for the following reaction: AH°; (kJ/mol) CHC13(1) + 3 HCl(g) -CH4(9) + 3 Cl2(9) AHºrn = ? CH (9) -75 CHC130) -134 HCl(9) -92 0 -217 kJ -335 kJ +151 kJ +335 kJ -485 kJ Submit Request Answer
1. Calculate AS, AH and AG for the following spontaneous (irreversible) process (with 3.0 mol of water at 1 atm). H2O (liquid, -15 °C) → H2O (solid, -15 °C) It is known that the heat of fusion of water at 0 °C is 1436 cal/mol; the heat capacity of liquid water is 18.0 cal/mol, the heat of capacity of ice is 8.7 cal/mol. H2O (liquid, -10 °C) → H2O (liquid, 0 °C). HOC -130 HO -15 To calculate AS, AH...