Question
draw a separation scheme to show how a pure product can be isolated.
Br. H + Brz BH Trans-stilbene C14H12 + Bromine --------→ 1,2-dibromo-1,2-diphenylethane + Br2 ----------> C14H12Br2
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Answer #1

In this reaction trans stilbene is trans substrate.

Br2 is reagent which give anti addition .

When at trans substrate anti addition occurs there is formation of a product which is either meso or pair of enantiomers(racemic mixture).

First attack of Pi electrons of double bond of alkene on Br2 ( attack on low lying sigma antibonding orbital of Br2). Formation of oi complex then Cyclic bromonium ion formed. Again Br- will attack. It has two sides for attack. Please see image

H + Brz yto complene plene Be a pothia Potha I Br Attack from below side e Peroducts Bromonium ion compeone Pathab Attack fr

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