Solution:
Propionic acid and sodium propionate forms an acidic buffer. Therefore, pH of buffer is calculated by Hendersen-Hasselbalch equation,
pH = pka + log [Sodium propionate] / [Propionic acid]
pka value for propionic acid = 4.87
Concentration of propionic acid and sodium propionate are:
[Propionic acid] = 0.10 M
[Sodium propionate ] = 0.20 M
Therefore,
pH = 4.87 + log 0.20 / 0.10
pH = 4.87 + log 2
pH = 4.87 + 0.3010 = 5.1710
pH = 5.17
e concentration of propionic acid in the solution? The K, for propionic acid is 1.3 x 105 (for HCaHsO2 from Table 16.1. 16.65 What is the pH of a 0.0 25 M aqueous solution of sodium propionate, NaC3HsO2? What is 4 5
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