Calculate overall energy changes in kilojoules per mole for the formation of SrCl from the elements. The following data are needed:
Eea for Cl = −348.6 kJ/mol
Ei1 for Sr = +549.5 kJ/mol
Ei2 for Sr = +1064 kJ/mol
Heat of sublimation for Sr = +164.4 kJ/mol
Bond dissociation energy for Cl2 = +243 kJ/mol
Lattice energy for SrCl2 = +2142 kJ/mol
Lattice energy (estimated) for SrCl = +685 kJ/mol
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Calculate overall energy changes in kilojoules per mole for the formation of SrCl from the elements....
Calculate the net energy change in kilojoules per mole that takes place on formation of BeF2(s) from the elements: Be(s)+F2(g)⟶BeF2(s) The following information is needed: Heat of sublimation for Be(s)= 325.8 kJ/mol Eea for F(g)= −328 kJ/mol Bond dissociation energy for F2(g)= 158 kJ/mol Ei1 for Be(g)= 899.5 kJ/mol Electrostatic interactions in BeF2(s)= −3505 kJ/mol Ei2 for Be(g)= 1757.1 kJ/mol
Calculate the energy change (in kilojoules per mole) for the formation of the following substances from their elements. CaF2 (The sublimation energy for Ca is +178.2 kJ/mol, Ei1 = +589.8 kJ/mol, Ei2 = +1145kJ/mol, and the lattice energy of CaF2 is 2630 kJ/mol.) Express the energy change in kilojoules per mole to four significant digits.
Calculate the net energy change in kilojoules per mole for the formation of KF(s) from the elements: K(s) + 1/2 F2(g) \rightarrow→KF(s). The following information is given: Heat of sublimation for K(s) = 89.2 kJ/mol, Eea for F(g) = –328 kJ/mol Bond dissociation energy for F2(g) = 158 kJ/mol, Ei for K(g) = 418.8 kJ/mol Electrostatic interactions in KF(s) = –821 kJ/mol
2. Use the following data to calculate the lattice energy (U) of NaCl(s) from sodium me chlorine: Enthalpy of formation (4H) for NaCl(s) - -411 kJ/mol Enthalpy of sublimation (4Hub) of Na 107.3 kJ/mol The first ionization energy of Na (E,)-495.8 kJ/mol The bond dissociation energy (D) of Clh- 243 kJ/mol The electron affinity of Cl (Eea)- 348.6 kJ/mol.
Can anyone help me with this using the proper steps? Thank you! Use the data given to calculate an overall energy change (in kilojoules per mole) for the formation of RbF2 from its elements. Express your answer to two significant figures and include the appropriate units. The estimated lattice energy for RbF2 is +2522kJ/mol. Eea for F(g)=?328kJ/mol Ei1 for Rb(g)=+403.0kJ/mol Ei2 for Rb(g)=+2633kJ/mol Heat of sublimation for Rb(g)=82.0kJ/mol Bond dissociation energy for F2(g)=+158kJ/mol
Calculate the net change in energy in kJ that takes place on formation of 50.44 moles of MgF2(s) from Mg(s) + F2(g) → MgF2(s) given the following information: Heat of sublimation for Mg(s) = 147.7 kJ/mol Bond dissociation energy for F2(g) = 158 kJ/mol Electrostatic interactions in MgF2(s) = -2957 kJ/mol Eea for F(g) = -328 kJ/mol Ei1 for Mg(g) = 737.7 kJ/mol Ei2 for Mg(g) = 1450.7 kJ/mol
Given the following information, construct a Born-Haber cycle to calculate the lattice energy of CaC2(s): Net energy change for the formation of CaC2(s)=−60kJ/mol Heat of sublimation for Ca(s)=+178kJ/mol Ei1 for Ca(g)=+590kJ/mol Ei2 for Ca(g)=+1145kJ/mol Heat of sublimation for C(s)=+717kJ/mol Bond dissociation energy for C2(g)=+614kJ/mol Eea1 for C2(g)=−315kJ/mol Eea2 for C2(g)=+410kJ/mol Express your answer using four sig figs
Using the Born Haber cycle in the previous question, and the following energies, calculate the standard energy of formation for Srl2 Enthalpy of sublimation of Sr(s) = 164 kJ/mol 1st ionization energy of Sr(g) = 549 kJ/mol 2nd ionization energy of Sr(g) - 1064 kJ/mol Enthalpy of sublimation of 12(s) = 62 kJ/mol Bond dissociation energy of 12(g) - 153 kJ/mol 1st electron affinity of l(g) = -295 kJ/mol Lattice energy of Srlz(s) = -1960 kJ/mol *Note: Do not include...
Consider the following information. The lattice energy of NaCl is ΔH lattice=−788 kJ/mol The enthalpy of sublimation of Na is ΔHsub=107.5 kJ/mol The first ionization energy of Na is IE1=496 kJ/mol. The electron affinity of Cl is ΔHEA=−349 kJ/mol. The bond energy of Cl2 is BE=243 kJ/mol. Determine the enthalpy of formation, ΔHf, for NaCl(s). ΔHf= kJ/mol
Consider the following information. The lattice energy of LiCl is ΔH lattice = −834 kJ/mol. The enthalpy of sublimation of Li is ΔH sub = 159.3 kJ/mol. The first ionization energy of Li is IE 1 = 520 kJ/mol. The electron affinity of Cl is ΔH EA = -349 kJ/mol. The bond energy of Cl2 is BE = 243 kJ/mol. Determine the enthalpy of formation, ΔHf, for LiCl(s).