91 169 305 330 335 389 393 394 402 410 420 449 452 455 459 465...

Question

Question

91 169 305 330 335 389 393 394 402 410 420 449 452 455 459 465 468 471 472 474 475 479 481 486 487 505 508 509 511 512 517 519 530 537

1. Construct a frequency distribution table using 10 classes. Start the lower limit with 91.

2. Using Chebyshev’s Theorem, find the range of data for which 75% of the data falls.

Answer 1

Answer #1

Here we have data :

91,169,305,330,335,389,393,394,402,410,420,449,452,455,459,465,468,471,472,474,475,479,481,486,487,505,508,509,511,512,517,519,530,537

2) Chebyshev's therom:

1 - (1 / K²) = 0.75

(1 / K² ) = 0.25

K = ± 2

Chebyshev’s theorem says that at least .75 of the values are within ± 2 of the mean.

Answer 2

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