Question

You require a 1 liter bag of 5% Dextrose solution. How many ml’s of 70% dextrose would give you the required amount to dilute to one liter to achieve a 5% solution?

Answer 1

We know that Q₁ × C₁ = Q₂ × C₂

Given data : C₁ =70%

Q₂ =1liter= 1000ml

C₂ = 5%

Q₁= unknown

Therefore, substituting the values,

$Q_{1} = \frac{Q_{2}C_{2}}{C_{1}} = \frac{1000ml\times0.05}{.70}=$   71.43ml

Ans: 71.43ml of 70% dextrose is needed.