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The test statistic in a two-tailed test is z= 2.34. Determine the P-value and decide whether,...
If you want to be 95% confident of estimating the population mean to within a sampling...
If you want to be 95% confident of estimating the population mean to within a sampling error of 20 and the standard deviation is assumed to be 80, what sample size is required? Click the icon to view a table of values for the standardized normal distribution. The sample size required is. (Round up to the nearest integer.) We were unable to transcribe this image1.1 0,8643 0.8665 0.8686 0.8708 0.8729 0,8749 0,8770 0.8790 0.8810 0.8830 12 0,8849 0.8869 0.8888 0.8907...
z .00 .01 .02 .03 .04 .05 .06 .07 .08 .09 z 0.0 0.5000 0.5040...
z .00 .01 .02
.03 .04 .05 .06
.07 .08 .09 z
0.0 0.5000 0.5040 0.5080
0.5120 0.5160 0.5199
0.5239 0.5279 0.5319
0.5359 0.0
0.1 0.5398 0.5438 0.5478
0.5517 0.5557 0.5596
0.5636 0.5675 0.5714
0.5753 0.1
0.2 0.5793 0.5832 0.5871
0.5910 0.5948 0.5987
0.6026 0.6064 0.6103
0.6141 0.2
0.3 0.6179...
You are the operations manager of a firm that uses the continuous inventory control system. Suppose...
You are the operations manager of a firm that uses the continuous inventory control system. Suppose the firm operates 50 weeks a year, 350 days, and has the following characteristics for its primary item: • Demand 543 units/week • Price paid to supplier = $156/unit • Ordering cost = $77/order • Holding cost = $14/unit/year • Lead time = 2 weeks • Standard deviation in weekly demand = 38 units To achieve a service level of 99%, the safety stock...
please solve both of questions QUESTIONS 1) [5Opts) Two random variables X and Y have have...
please solve both of questions
QUESTIONS 1) [5Opts) Two random variables X and Y have have the following joint distribution. A rondom variable Z is known to be the sum of these two random variables. The joint probability distribution of X and Y is given as fxy(x,y) = kye-*e-> 0<x0<y Calculate var(2) 2) [50pts] Given the joint distribution function OS Xys 1 Calculate A and B 0.07 0.00 0.00 0.5000 0.5398 0.5793 0.6179 0.6554 0.6915 0.7257 0.7580 0.7881 0.8150 0.8413...
mean of 81 and standard devation of 25 3-38 PM Wed Oct 9 Use the Lea...
mean of 81 and standard devation of 25
3-38 PM Wed Oct 9 Use the Lea TUTULT S knewton.com ardes du VIGLUT Question What is the probability that the sample mean for a sample of size 150 will be more than 822 • Use the results from above in your calculation and round your answer to the nearest percent. You may use a calculator or the portion of the z.table given below. Z 0.00 0.01 0.02 0.03 0.04 0.05 0.06...
SCUTE. V ULIC 13 01 '16 (12 complele) 7.2.47 The mean incubation time of fertilized eggs...
SCUTE. V ULIC 13 01 '16 (12 complele) 7.2.47 The mean incubation time of fertilized eggs is 21 days. Suppose the incubation times are approximately normally distributed with a standard deviation of 1 day (a) Determine the 10th percentile for incubation times. (b) Determine the incubation times that make up the middle 97%. = Click the icon to view a table of areas under the normal curve. (a) The 10th percentile for incubation times is days. (Round to the nearest...
If you use a 0.05 level of significance in a two-tail hypothesis test, what decision will...
If you use a 0.05 level of significance in a two-tail hypothesis test, what decision will you make if ZSTAT = - 2.29? Click here to view page 1 of the cumulative standardized normal distribution table. Click here to view page 2 of the cumulative standardized normal distribution table Determine the decision rule. Select the correct choice below and fill in the answer box(es) within your choice. (Round to two decimal places as needed.) O A. Reject Ho []<ZsTAT< ]...
A company begins a review of ordering policies for its continuous review system by checking the c...
A company begins a review of ordering policies for its continuous review system by checking the current policies for a sample of SKUs. Following are the characteristics of one item: follows≻Demand (D) = 80 units/week (Assume 50 weeks per year) follows≻Ordering and setup cost (S) =90/order follows≻Holding cost (H) =18/unit/year follows≻Lead time (L) = 22 week(s) follows≻Standard deviation of weekly demand = 2020 units follows≻Cycle-service level = 9292 percent follows≻EOQ = 200200 units Using the above information, develop the best...
Determine the area under the standard normal curve that lies to the right of a(Z) =...
Determine the area under the standard normal curve that lies to
the right of a(Z) = -0.42, b(Z) =0.54, c(Z) = - 0.76, and d(Z) =
-1.91
MyStatLab Data Set - Google Chrome statcrunch.com/app/?dlim=comma&ft=false&dataurl=https%3a%2f%2fxlitemprod.pearsoncmg.com%2fGetPlayerFile.ashx%3fguid%3d1e9f4376-4819-4d55-8ca0-c41ee702bb63 MyStatLab Data Set StatCrunch Applets Edit Data | StatGraph | Help Row vari vari var2 var12 var13 var14 ve -3.4 -3.3 -3.2 -2.9 -2.8 -2.7 -2.6 -2.5 -2.4 -2.3 HNMONOFHHHHHNNNNNNNNNN -2.2 -2.1 -2 -1.9 0.0003 0.0005 0.0007 0.001 0.0013 0.0019 0.0026 0.0035 0.0047 0.0062 0.0082 0.0107...
Weight (gm) 8.499993 8.499998 8.499996 8.499996 8.499987 8.499987 8.499996 8.500008 8.499...
Weight (gm)
8.499993
8.499998
8.499996
8.499996
8.499987
8.499987
8.499996
8.500008
8.499997
8.499996
Steps 1. Open the Excel workbook almer-jones.xls 2. Type the text Sample mean weight in cell C1 and calculate the sample mean weight in cell C2 3. Type the text Test statistic in cell C4 and calculate the test statistic in cell C5 using the formula y-8.5 o/V10 4. Use the standard normal tables to determine the P-value 5. Hence determine whether the claim that the true weight...
If you want to be 95% confident of estimating the population mean to within a sampling error of 20 and the standard deviation is assumed to be 80, what sample size is required? Click the icon to view a table of values for the standardized normal distribution. The sample size required is. (Round up to the nearest integer.) We were unable to transcribe this image1.1 0,8643 0.8665 0.8686 0.8708 0.8729 0,8749 0,8770 0.8790 0.8810 0.8830 12 0,8849 0.8869 0.8888 0.8907...
z .00 .01 .02
.03 .04 .05 .06
.07 .08 .09 z
0.0 0.5000 0.5040 0.5080
0.5120 0.5160 0.5199
0.5239 0.5279 0.5319
0.5359 0.0
0.1 0.5398 0.5438 0.5478
0.5517 0.5557 0.5596
0.5636 0.5675 0.5714
0.5753 0.1
0.2 0.5793 0.5832 0.5871
0.5910 0.5948 0.5987
0.6026 0.6064 0.6103
0.6141 0.2
0.3 0.6179...
You are the operations manager of a firm that uses the continuous inventory control system. Suppose the firm operates 50 weeks a year, 350 days, and has the following characteristics for its primary item: • Demand 543 units/week • Price paid to supplier = $156/unit • Ordering cost = $77/order • Holding cost = $14/unit/year • Lead time = 2 weeks • Standard deviation in weekly demand = 38 units To achieve a service level of 99%, the safety stock...
please solve both of questions
QUESTIONS 1) [5Opts) Two random variables X and Y have have the following joint distribution. A rondom variable Z is known to be the sum of these two random variables. The joint probability distribution of X and Y is given as fxy(x,y) = kye-*e-> 0<x0<y Calculate var(2) 2) [50pts] Given the joint distribution function OS Xys 1 Calculate A and B 0.07 0.00 0.00 0.5000 0.5398 0.5793 0.6179 0.6554 0.6915 0.7257 0.7580 0.7881 0.8150 0.8413...
mean of 81 and standard devation of 25
3-38 PM Wed Oct 9 Use the Lea TUTULT S knewton.com ardes du VIGLUT Question What is the probability that the sample mean for a sample of size 150 will be more than 822 • Use the results from above in your calculation and round your answer to the nearest percent. You may use a calculator or the portion of the z.table given below. Z 0.00 0.01 0.02 0.03 0.04 0.05 0.06...
SCUTE. V ULIC 13 01 '16 (12 complele) 7.2.47 The mean incubation time of fertilized eggs is 21 days. Suppose the incubation times are approximately normally distributed with a standard deviation of 1 day (a) Determine the 10th percentile for incubation times. (b) Determine the incubation times that make up the middle 97%. = Click the icon to view a table of areas under the normal curve. (a) The 10th percentile for incubation times is days. (Round to the nearest...
If you use a 0.05 level of significance in a two-tail hypothesis test, what decision will you make if ZSTAT = - 2.29? Click here to view page 1 of the cumulative standardized normal distribution table. Click here to view page 2 of the cumulative standardized normal distribution table Determine the decision rule. Select the correct choice below and fill in the answer box(es) within your choice. (Round to two decimal places as needed.) O A. Reject Ho []<ZsTAT< ]...
Determine the area under the standard normal curve that lies to
the right of a(Z) = -0.42, b(Z) =0.54, c(Z) = - 0.76, and d(Z) =
-1.91
MyStatLab Data Set - Google Chrome statcrunch.com/app/?dlim=comma&ft=false&dataurl=https%3a%2f%2fxlitemprod.pearsoncmg.com%2fGetPlayerFile.ashx%3fguid%3d1e9f4376-4819-4d55-8ca0-c41ee702bb63 MyStatLab Data Set StatCrunch Applets Edit Data | StatGraph | Help Row vari vari var2 var12 var13 var14 ve -3.4 -3.3 -3.2 -2.9 -2.8 -2.7 -2.6 -2.5 -2.4 -2.3 HNMONOFHHHHHNNNNNNNNNN -2.2 -2.1 -2 -1.9 0.0003 0.0005 0.0007 0.001 0.0013 0.0019 0.0026 0.0035 0.0047 0.0062 0.0082 0.0107...
Weight (gm)
8.499993
8.499998
8.499996
8.499996
8.499987
8.499987
8.499996
8.500008
8.499997
8.499996
Steps 1. Open the Excel workbook almer-jones.xls 2. Type the text Sample mean weight in cell C1 and calculate the sample mean weight in cell C2 3. Type the text Test statistic in cell C4 and calculate the test statistic in cell C5 using the formula y-8.5 o/V10 4. Use the standard normal tables to determine the P-value 5. Hence determine whether the claim that the true weight...
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