*** Please use TI-83+ calculator to solve this problem ***
You wish to test the following claim (HaHa) at a significance
level of α=0.02α=0.02.
Ho:p1=p2Ho:p1=p2
Ha:p1<p2Ha:p1<p2
You obtain 465 successes in a sample of size n1=592n1=592 from the
first population. You obtain 593 successes in a sample of size
n2=687n2=687 from the second population. For this test, you should
NOT use the continuity correction, and you should use the normal
distribution as an approximation for the binomial
distribution.
What is the test statistic for this sample? (Report answer accurate
to three decimal places.)
test statistic =
What is the p-value for this sample? (Report answer accurate to
four decimal places.)
p-value =
The p-value is...
This test statistic leads to a decision to...
As such, the final conclusion is that...
(a)
n1 = 592
p1 = 465/592 = 0.7855
n2 = 687
p2 = 593/687 =0.8632
Q = 1 - P = 0.1728
Test statistic is:
Z = (0.7855 - 0.8632)/0.0212 = - 3.665
So,
test statistic is:
- 3.665
(b)
To find P - Value:
In TI-83+ calculator:
Select 5:1-PropZTest
Enter above statistical data.
Select Calculate.
We get:
p = 0.0001
(c)
Correct option:
less than or equal to
(d)
Correct option:
reject the null
(e)
correct option:
The sample datasupport the claim that the first population proportion is less than the second population proportion.
*** Please use TI-83+ calculator to solve this problem *** You wish to test the following...
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